Find the mean and standard deviation of the sampling distribution. Show your work.

Short Answer

Expert verified

The required mean and standard deviation are -0.10 and 0.097 respectively.

Step by step solution

01

Given Information

Proportion of red crackers in Bag 1p1=25%

=0.25.

Proportion of red crackers in Bag 2p2=35%

=0.35.

Number of crackers in Bag 1n1=50.

Number of crackers in Bag 2n2=40.

02

Explanation

The formulas to compute the mean and standard deviation are:

Meanμp^1-p^2=p1-p2Standard deviationσp^1-p^2=p11-p1n1+p21-p2n2

The mean and standard deviation can be computed as:

Meanμp^1-p^2=p1-p2

=0.25-0.35

=-0.10

Now,

Standard deviationσp^1-p^2=p11-p1n1+p21-p2n2

=0.25(1-0.25)50+0.35(1-0.65)40

=0.097

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