How many people live in South African households? To find out, we collected data from an SRS of 48 out of the over 700,000 South African students who took part in

the CensusAtSchool survey project. The mean number of people living in a household was 6.208; the standard deviation was 2.576.

(a) Is the Normal condition met in this case? Justify your answer.

(b) Maurice claims that a 95% confidence interval for the population mean is 6.208±1.960.37247. Explain why this interval is wrong. Then give the correct interval.

Short Answer

Expert verified

a. Yes, the Normal condition is met in this case

b. The confidence interval is(5.4565,6.9594)

Step by step solution

01

introduction

Collected data from an SRS of 48out of the over 700000South African students who took part in the Census At School survey project.

The mean number of people living in a household was 6.208; the standard deviation was 2.567

02

explanation part (a)

we have,

sample standard deviation s =2.567

sample size n =48and sample meanx-=6.208

The normal condition is met in this case because to build the confidence interval either the sample size ought to be at least30or the population should be distributed typically as the sample size is over 30.30

03

explanation part (b)

Calculating confidence interval by using

sample standard deviation s =2.567

sample size n = 48and sample meanx-=6.208

CI = 6.208±2.0212.56748

Hence the confidence interval is(5.4565,6.9594)

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Most popular questions from this chapter

I collect an SRS of size n from a population and compute a 95%confidence interval for the population proportion. Which of the following would produce a new confidence interval with larger width (larger margin of error) based on these same data?

(a) Use a larger confidence level.

(b) Use a smaller confidence level.

(c) Increase the sample size.

(d) Use the same confidence level, but compute the interval n times. Approximately5% of these intervals will be larger.

(e) Nothing can guarantee absolutely that you will get a larger interval. One can only say that the chance of obtaining a larger interval is 0.05.

Losing weight A Gallup Poll in November 2008found that 59%of the people in its sample said “Yes” when asked, “Would you like to lose weight?” Gallup announced: “For results based on the total sample of national adults, one can say with 95% confidence that the margin of (sampling) error is ±3percentage points.”

(a) Explain what the margin of error means in this setting.

(b) State and interpret the 95% confidence interval.

(c) Interpret the confidence level.

What critical value tfrom Table B would you use for a 90%confidence interval for the population mean based on an SRS of size 77? If possible, use technology to find a more accurate value of t. What advantage does the more accurate df provide?

98% Confidence find z*for a98%confidence interval using table A or tour calculator. show your method.

59.Blood pressure A medical study finds that x¯=114.9and Sx=21.88for the seated systolic blood pressure of the 27 members of one treatment group. What is the standard error of the mean? Interpret this value in context.

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