High tuition costs Glenn wonders what proportion of the students at his school think that tuition is too high. He interviews an SRS of 50 of the 2400 students at his college. Thirty-eight of those interviewed think tuition is too high.

Short Answer

Expert verified

All three conditions for confidence interval is satisfied.

Step by step solution

01

Step-1 Given Information

Given in the question that,

Population size=2400

number of sample=50

number of success=38we have to calculate what proportion of the students at his school think that tuition is too high.

02

Step-2 Explanation

Three conditions must be met in order to construct a confidence interval. Random, Independent, and Normal are the conditions.

The requirement of randomness is met because the sample was drawn at random among the college students. The requirement for independence is satisfied because the sample size is less than 10% of the population size. In the study, there are 38success stories and 12failure stories. Because both the success and the success rate are more than ten. As a result, the typical condition is met. As a result, all three confidence interval conditions are met.

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Most popular questions from this chapter

One reason for using a tdistribution instead of the standard Normal curve to find critical values when calculating a level C confidence interval for a population mean is that

(a) zcan be used only for large samples.

(b) zrequires that you know the population standard deviation σ.

(c) zrequires that you can regard your data as an SRS from the population.

(d) the standard Normal table doesn't include confidence levels at the bottom.

(e) a zcritical value will lead to a wider interval than a tcritical value.

It’s critical Find the appropriate critical value for constructing a confidence interval in each of the following settings.

(a) Estimating a population proportion p at a 94%confidence level based on an SRS of size 125.

(b) Estimating a population mean M at a 99%confidence level based on an SRS of size 58.

Researchers were interested in comparing two methods for estimating tire wear. The first method used the amount of weight lost by a tire. The second method used the amount of wear in the grooves of the tire. A random sample of 16tires was obtained. Both methods were used to estimate the total distance traveled by each tire. The table below provides the two estimates (in thousands of miles) for each tire.

(a) Construct and interpret a 95%confidence interval for the mean difference μin the estimates from these two methods in the population of tires.

(b) Does your interval in part (a) give convincing evidence of a difference in the two methods of estimating tire wear? Justify your answer.

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National Cancer Institute spent 5 years and $5million gathering data on this question. The researchers compared 638children who had leukemia with620who did not. They went into the homes and actually measured the magnetic fields in children's bedrooms, in other rooms, and at the front door. They recorded facts about power lines near the family home and also near the mother's residence when she was pregnant. Result: no connection between leukemia and exposure to magnetic fields of the kind produced by power lines was found.

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