98% Confidence find z*for a98%confidence interval using table A or tour calculator. show your method.

Short Answer

Expert verified

The value of z*is 2.33

Step by step solution

01

Step-1 Given Information

Given in the question that the confidence level is98%we have to find the value ofz*.

02

Step-2 Explanation

Convert the confidence level 98%into decimal:

98100=0.98

use table A,

zα2=z0.01=2.33

z*=2.33

Hence the value ofz*is2.33

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use Table B to find the critical value t* that you would use for a confidence interval for a population mean M in each of the following situations. If possible, check your answer with technology.

(a) A 98% confidence interval based on n=22observations.

(b) A 90%confidence interval from an SRS of 10observations.

(c) A 95% confidence interval from a sample of size7.

62. Blink When two lights close together blink alternately, we “see” one light moving back and forth if the time between blinks is short. What is the
longest interval of time between blinks that preserves the illusion of motion? Ask subjects to turn a knob that slows the blinking until they “see” two lights rather than one light moving. A report gives the results in the form “mean plus or minus the standard error of the mean.” Data for 12 subjects are summarized as 251±45 (in milliseconds).
(a) Find the sample standard deviation sx for these measurements. Show your work.
(b) Explain why the interval 251±45 is not a confidence interval.

64. Vitamin C content Several years ago, the U.S. Agency for International Development provided 238,300 metric tons of corn-soy blend (CSB) for
emergency relief in countries throughout the world. CSB is a highly nutritious, low-cost fortified food. As part of a study to evaluate appropriate vitamin C levels in this food, measurements were taken on samples of CSB produced in a factory. The following data are the amounts of vitamin C,

measured in milligrams per 100grams (mg/100 g) of blend, for a random sample of size8 from one production run:
2631232211221431
Construct and interpret a95%confidence interval for the mean amount of vitamin C M in the CSB from this production run.

61. Willows in Yellowstone Writers in some fields summarize data by giving x¯and its standard error rather than x¯and sx. Biologists studying willow trees in Yellowstone National Park reported their results in a table with columns labeled x¯+SE. The table entry for the heights of willow trees (in centimeters) in one region of the park was 61.55±19.03.The researchers measured a total of23 trees.
(a) Find the sample standard deviation sx for these measurements. Show your work.
(b) Explain why the given interval is not a confidence interval for the mean height of willow trees in this region of the park.

The AP Statistics class in Exercise 1 also asked an SRS of 20 boys at their school how many shoes they have. A 95% confidence interval for the difference in the population means (girls – boys) is 10.9 to 26.5. Interpret the confidence interval and the confidence level.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free