Why men and women play sports Do men and women participate in sports for the same reasons? One goal for sports participants is social comparision—the desire to win or to do better than other people. Another is mastery—the desire to improve one’s skills or to try one’s best. A study on why students participate in sports collected data from independent random samples of 67 male and 67 female under-graduates at a large university 15 Each student was classified into one of four categories based on his or her responses to a questionnaire about sports goals. The four categories were high social comparison– high mastery (HSC-HM), high social comparison– low mastery (HSC-LM), low social comparison–high mastery (LSC-HM), and low social comparison–low mastery (LSC-LM). One purpose of the study was to compare the goals of male and female students. Here are the data displayed in a two-way table: Observed Counts for Sports Goals

(a) Check that the conditions for performing the chi-square test are met.

(b) Use Table C to find the P-value. Then use your calculator’s C2cdf command.

(c) Interpret the P-value from the calculator in context.

(d) What conclusion would you draw? Justify your answer.

Short Answer

Expert verified

a)The given information satisfies each condition. As a result, the chi-square test can be applied to the given dataset.

b)The p-value is0.1.621759222E-5.

c) If the null hypothesis is true, the p-value represents the probability of obtaining results that are as extreme as the test statistic value. If there is no relationship between gender and sports goal, the likelihood of getting a sample as extreme or more extreme than the given sample is 0.1.621759222E-5.

d) There is enough evidence to conclude that there is a relationship between the variables' goal and sex.

Step by step solution

01

Part a Step 1 Given Information

Given that

02

Part a Step 2 Explanation

The expected table is

The following conditions must be met in order to use the chi-square test: - Two categorical variables.

- Each variable has two or more categories.

- Observation independence - Expected frequency for each cell is at least 1 or should be at least 5 for the majority (80%) of the cells.

Because the given information satisfies each condition. As a result, the chi-square test can be applied to the given dataset.

03

Part b Step 1 Given Information

The test statistics is24.8978.

04

Part b Step 2 Explanation

df=(n-1)(m-1)

p-value=Pχ2>χtext2

df=(4-1)(2-1)

df=(4-1)(2-1)

= 3

There is the following commend to find p-value on TI83,

"χ2cdf(24.8978,99,3)"

The output is,

localid="1653293946609" Sothe p-value is0.1621759222E-5.

05

Part c Step 1 Given Information

06

Part c Step 2 Explanation

H0:There is no difference in the distribution sports goalsfor male and female undergraduates at the university

H1:There is a difference in the distribution sports goalsfor male and female undergraduates at the university

If the null hypothesis is true, the p-value represents the probability of obtaining results that are as extreme as the test statistic value. If there is no relationship between gender and sports goal, the likelihood of getting a sample as extreme or more extreme than the given sample is0.1621759222E-5.

07

Part d Step 1 Given Information

08

Part d Step 2 Explanation

When the pvalue is less than the level of significance, the null hypothesis is rejected.

In this case, thepvalue is less than the level of significance. As a result, the null hypothesis is rejected.

As a result, there is enough evidence to conclude that there is a relationship between the variables goal and sex.

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Most popular questions from this chapter

Biologists wish to mate pairs of fruit flies having genetic makeup RrCc, indicating that each has one dominant gene (R) and one recessive gene (r) for eye color, along with one dominant (C) and one recessive (c) gene for wing type. Each offspring will receive one gene for each of the two traits from each parent. The following Punnett square shows the possible combinations of genes received by the offspring:

Any offspring receiving an R gene will have red eyes, and any offspring receiving a C gene will have straight wings. So based on this Punnett square, the biologists predict a ratio of 9 red-eyed, straight-winged (x):3 red-eyed, curly-winged (y):3 white-eyed, straight-winged (z):1 white-eyed, curly-winged (w) offspring. To test their hypothesis about the distribution of offspring, the biologists mate a random sample of pairs of fruit flies. Of 200 offspring, 99 had red eyes and straight wings, 42 had red eyes and curly wings, 49 had white eyes and straight wings, and 10 had white eyes and curly wings. Do these data differ significantly from what the biologists have predicted? Carry out a test at the A  0.01 significance level

The cell in the table that contributes the most to the chi-square statistic is (a) Female, 5050 chance.

(b) Male, 5050 chance.

(c) Female, almost certain.

(d) Male, almost certain.

(e) All the cells contribute equally to the test statistic.

The expected count of females who respond “almost certain” is

(a) 464.6.

(b) 891.2.

(c) 1038.8.

(d) 1174.

(e) None of these.

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Interpret the p-value from the calculator in context.

A Type I error would occur if we conclude that

(a) HCC wiring caused cancer when it actually didn't.

(b) HCC wiring didn't cause cancer when it actually did.

(c) there is no association between the type of wiring and the form of cancer when there actually is an association.

(d) there is an association between the type of wiring and the form of cancer when there actually is no association.

(e) the type of wiring and the form of cancer have a positive correlation when they actually don't.

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