How is the hatching of water python eggs influenced by the temperature of the snake’s nest? Researchers randomly assigned newly laid eggs to one of three water temperatures: hot, neutral, or cold. Hot duplicates the extra warmth provided by the mother python, and cold duplicates the absence of the mother. Here are the data on the number of eggs and the number that hatched

(a) Make a two-way table of temperature by outcome (hatched or not). Calculate the proportion of eggs in each group that hatched. The researchers believed that eggs would not hatch in cold water. Do the data support that belief?

(b) Are the differences between the three groups statistically significant? Give appropriate evidence to support your answer

Short Answer

Expert verified

(a) The two-way table of temperature by the outcome is shown in the table

and yes the data support the belief.

(b) The differences between the three groups are not statistically significant.

Step by step solution

01

Part (a) Step 1: Given information

The given data is

02

Part (a)  Step 2: Explanation

The number of eggs not hatched is the number of eggs decreased by the number of eggs that hatched.

The proportions in each group is the number of eggs divided by the row total given in the last column:

We can see that the fraction is lowest in cold water, confirming the researcher's hypothesis. However, this percentage is still quite high.

03

Part (b) Step 1: Given information

The given data is

04

Part (b) Step 2: Explanation

Observed counts

The expected counts are the row total multiplied by the column total, divided by the sample size187.

The chi-square statistic is the sum of squared deviations (between observed and expected counts) divided by the expected count:

localid="1650643863502" χ2=(16-18.6257)218.6257+(11-8.3743)28.3743+(38-38.631)238.631+(18-17.369)217.369+(75-71.7433)271.7433+(29-32.2567)232.2567=1.703

The interval for the P-value can then be in found in table C in the column title which have the X2-value in the corresponding interval in the row with

localid="1650643872824" df=(c-1)(r-1)=(3-1)(2-1)=2

P>0.25

If the P-value is smaller than the significance level, then the null hypothesis is rejected

P>0.05FailtorejectH0

There is not sufficient evidence that there is an association between the variables.

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Most popular questions from this chapter

Stress and heart attack You read a newspaper article that describes a study of whether stress management can help reduce heart attacks. The 107subjects all had reduced blood flow to the heart and so were at risk of a heart attack. They were assigned at random to three groups. The article goes on to say: One group took a four-month stress management program, another underwent a four-month exercise program, and the third received usual heart care from their personal physicians. In the next three years, only three of the 33people in the stress management group suffered “cardiac events,” defined as a fatal or non-fatal heart attack or a surgical procedure such as a bypass or angioplasty. In the same period, seven of the 34people in the exercise group and 12out of the 40 patients in usual care suffered such events.36

(a) Use the information in the news article to make a two-way table that describes the study results.

(b) What are the success rates of the three treatments in preventing cardiac events?

(c) Is there a significant difference in the success rates for the three treatments? Give appropriate statistical evidence to support your answer.

The P-value for a chi-square goodness-of-fit test is 0.0129. The correct conclusion is

(a) reject H0at α=0.05; there is strong evidence that the trees are randomly distributed.

(b) reject H0at α=0.05; there is not strong evidence that the trees are randomly distributed.

(c) reject H0at α=0.05; there is strong evidence that the trees are not randomly distributed.

(d) fail to reject H0at α=0.05; there is not strong evidence that the trees are randomly distributed.

(e) fail to reject H0at α=0.05; there is strong evidence that the trees are randomly distributed.

In the United States, there is a strong relationship between education and smoking: well-educated people are less likely to smoke. Does a similar relationship hold in France? To find out, researchers recorded the level of education and smoking status of a random sample of 459 French men aged 20 to 60 years. 11 The two-way table below displays the data.

(a) Is the relationship between smoking status and educational level statistically significant? Give appropriate evidence to support your answer.

(b) Which cell in the table contributes most to the relationship in part (a)? Justify your answer.

Aw, nuts! Calculate the chi-square statistic for the data in Exercise 1. Show your work.

An appropriate null hypothesis to test whether the trees in the forest are randomly distributed is

(a) H0:μ=25, where μ=the mean number of trees in each quadrant.

(b) H0:p=0.25, where p=the proportion of all trees in the forest that are in Quadrant 1.

(c) H0:n1=n2=n3=n4=25, where niis the number of trees from the sample in Quadrant i.

(d) H0:p1=p2=p3=p4=0.25, where piis the actual proportion of trees in the forest that are in Quadrant i.

(e) H0:p^1=p^2=p^3=p^4=0.25, where p^iis the proportion of trees in the sample that are in Quadranti.

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