A study conducted in Charlotte, North Carolina, tested the effectiveness of three police responses to spouse abuse: (1) advise and possibly separate the couple, (2) issue a citation to the offender, and (3) arrest the offender. Police officers were trained to recognize eligible cases. When presented with an eligible case, a police officer called the dispatcher, who would randomly assign one of the three available treatments to be administered. There were a total of 650 cases in the study. Each case was classified according to whether the abuser was subsequently arrested within six months of the original incident.

(a) Explain the purpose of the random assignment in the design of this study.

(b) Construct a well-labeled graph that is suitable for comparing the effectiveness of the three treatments.

(c) We want to use these data to perform a test ofH0:p1=p2=p3wherepi=

the true proportion of spouse abusers like the ones in this study who would be arrested again within six months after receiving treatment \(i\). State an appropriate alternative hypothesis.

(d) Assume that all the conditions for performing the test in part (b) are met. The test yields χ2=5.063and a P-value of 0.0796Interpret this P-value in context. What conclusion should we draw from the study?

Short Answer

Expert verified

a. Including all variables in a study is the purpose of the random assignment in the design of the study.

b.

c. Ha:At least one ofpiis differentis the alternative hypotheses.

d. There is adequate evidence to reject the assumption that all proportions are equal at the5% significance level.

Step by step solution

01

Part (a)Step 1: Given information

A study done in Charlotte, North Carolina, examined the effectiveness of three police responses to marital abuse, as stated in the question. The study included a total of 650 patients. Each case was categorized based on whether or not the abuser was apprehended within six months of the initial event.

We need to clarify why the random assignment was used in this study's design.

02

Part(a) Step 2: Explanation

Let's consider the given table:

TreatmentNo subsequent arrestSubsequent arrestAdvise and separate18725Citation18143Arrest17539

Random assignment was used in this study to include all of the factors and eliminate the effect of any variables that were not included in the study.

03

Part(b) Step 1: Given information

Given in the question that,

TreatmentNo subsequent arrestSubsequent arrestAdvise and separate18725Citation18143Arrest17539

We need to construct a well-labeled graph for comparing the effectiveness of the three treatments.

04

Part (b) Step 2: Explanation

The diagram is made in the following way:

05

Part(c) Step 1: Given information

We have to use these data to perform a test of H0: P1=P2=P3, where pi=the true proportion of spouse abusers like the ones in this study who would be arrested again within six months after receiving treatmenti.

06

Part(c) Step 2: Explanation

The following are the null and alternative hypotheses:

H0:p1=p2=p3

Ha:At least one of piis different

07

Part(d) Step 1: Given information

Assume that all the conditions for performing the test in part (b) are met. The test yields x2=5.063and a P-value of 0.0796. We need to interpret this P-value in context.

08

Part (d) Step 2: Explanation

0.05is the p-value. The null hypothesis is found to be false. Thus, there is adequate evidence to reject the assumption that all proportions are equal at the5percent significance level.

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Most popular questions from this chapter

Refer to Exercises 1 and 3.

(a) Confirm that the expected counts are large enough to use a chi-square distribution. Which distribution (specify the degrees of freedom) should you use?

(b) Sketch a graph like Figure 11.4 (page 683) that shows the P-value.

(c) Use Table C to find the P-value. Then use your calculator’s C2cdf command

(d) What conclusion would you draw about the company’s claimed distribution for its deluxe mixed nuts? Justify your answer.

Software gives test statistic χ2=69.8and P-value close to 0 . The correct interpretation of this result is

(a) the probability of getting a random sample of 4877teens that yields a value of χ2of 69.8or larger is basically 0.

(b) the probability of getting a random sample of 4877teens that yields a value of χ2of 69.8or larger if H0is true is basically 0.

(c) the probability of making a Type I error is basically 0.

(d) the probability of making a Type II error is basically 0.

(e) it's very unlikely that these data are true.

The category that contributes the largest component to theχ2statistic is

(a) White.

(c) Hispanic.

(b) Black.

(d) Other.

(e) The answer cannot be determined since this is only a sample.

After randomly assigning subjects to treatments in a randomized comparative experiment, we can compare the treatment groups to see how well the random assignment worked. We hope to find no significant differences among the groups. A study on how to provide premature infants with a substance essential to their development assigned infants at random to receive one of four types of supplements, called PBM, NLCP, PL-LCP, and TG-LCP. The subjects were 77premature infants. In the experiment, 20were assigned to the PBM group and 19to each of the other treatments.

(a) The random assignment resulted in 9females in the TG-LCP group and 11 females in each of the other groups. Make a two-way table of the group by gender. Calculate the proportion of females in each treatment group. Does it appear that the random assignment roughly balanced the groups by gender? Explain.

(b) Are the differences between the groups statistically significant? Give appropriate evidence to support your answer.

How do U.S. residents who travel overseas for leisure differ from those who travel for business? The following is the breakdown by occupation:

Explain why we can’t use a chi-square test to learn whether these two distributions differ significantly.

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