SAT versus ACT Eleanor scores 680 on the SAT Mathematics test. The distribution of SAT scores is

symmetric and single-peaked, with mean 500and standard deviation 100. Gerald takes the American College Testing (ACT) Mathematics test and scores 27. ACT scores also follow a symmetric, singlepeaked distribution—but with mean 18 and standard deviation 6. Find the standardized scores for both students. Assuming that both tests measure the same kind of ability, who has the higher score?

Short Answer

Expert verified

The standardized score for E is 150 and the standardized score for G is 180

Step by step solution

01

Step 1. Given

The average score on the SAT Mathematics test is 500. Eleanor received a 680 on the SAT Mathematics test. The SAT Mathematics test has a standard deviation of 100. Gerald received a 27on the ACT Mathematics test. The average ACT Mathematics test score is 18 points. The ACT Mathematics exam score has a standard deviation of 6 points.

02

Step 2. Concept

The inflection points are the points where the curve shifts from being concave up to being concave down. These inflection points are always one standard deviation distant from the mean on a normal density curve.

03

Step 3. Explanation

Eis's standardized score is shown below.

z(Eleanor)=xμσ=680500100=1.80

The standardized score for G can be found in the table below.

z(Gerald)=xμσ=27186=1.50

E's score of 680was 1.80standard deviations higher than the mean, whereas G's score of27was 1.50standard deviations higher. Therefore, the standardized score for Eis 180 and the standardized score for G is 150

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Most popular questions from this chapter

T2.3. Rainwater was collected in water collectors at 30different sites near an industrial complex, and the amount of acidity (pH level) was measured. The mean and standard deviation of the values are 4.60and 1.10, respectively. When the pH meter was recalibrated back at the laboratory, it was found to be in error. The error can be corrected by adding 0.1pHunits to all of the values and then multiplying the result by 1.2. The mean and standard deviation of the corrected pH measurements are

(a)5.64,1.44

(b)5.64,1.32

(c)5.40,1.44

(d)5.40,1.32

(e)5.64,1.20

Questions T2.9 and T2.10 refer to the following setting. Until the scale was changed in 1995, SAT scores were based on a scale set many years ago. For Math scores, the mean under the old scale in the 1990swas 470and the standard deviation was 110. In 2009, the mean was 515and the standard deviation was 116 .
T2.10. Jane took the SAT in 1994and scored 500. Her sister Colleen took the SAT in 2009and scored 530. Who did better on the exam, and how can you tell?
(a) Colleen-she scored 30 points higher than Jane.
(b) Colleen-her standardized score is higher than Jane's.
(c) Jane-her standardized score is higher than Colleen's.
(d) Jane-the standard deviation was bigger in 2009.
(e) The two sisters did equally well-their z-scores are the same.

T2.6. The figure shown is the density curve of a distribution. Five of the seven points marked on the density curve make up the five-number summary for this distribution. Which two points are not part of the five-number summary?

(a) Band E
(b) C and F
(c) C and E
(d) B and F
(e) A and G.

Two measures of center are marked on the density curve shown.

(a) The median is at the yellow line and the mean is at the red line.

(b) The median is at the red line and the mean is at the yellow line.

(c) The mode is at the red line and the median is at the yellow line.

(d) The mode is at the yellow line and the median is at the red line.

(e) The mode is at the red line and the mean is at the yellow line.

Suppose that you convert the class’s heights from inches to centimeters (1inch=2.54cm). Describe the effect this will have on the shape, center, and spread of the distribution.

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