R2.7 Standard Normal areas Use Table A to find the proportion of observations from a standard Normal distribution that falls in each of the following regions. In each case, sketch a standard Normal curve and shade the area representing the region.

(a) z-2.25

(b)z-2.25

(c) role="math" localid="1649401025226" z>1.77

(d) -2.25<z<1.77

Short Answer

Expert verified

a. z-2.25=0.0122

b. z-2.25=0.9878

c. z>1.77=0.0384

d.-2.25<z<1.77=0.9494

Step by step solution

01

Given information (Part a)

Use Table A to find the proportion of observations from a standard Normal distribution

z-2.25=?

02

Explanation (Part a)

Table A contains probabilities of values smaller than a z-score.

Thus the probability is given in table A in the row with -2.2and in the column of 5.

P(z<-2.25)=0.0122

03

Final Answer (Part a)

P(Z<-2.25): in a z-table having area to the left of z, locate -2.2 in the left most column. Move across the row to the right under column 0.05and get value0.0122

04

Given information (Part b) 

Use Table A to find the proportion of observations from a standard Normal distribution

z-2.25=?

05

Explanation (Part b) 

Since this is continuous distribution, P(Z-2.25)=P(Z>-2.25)

Area to the right of -2.25

P(7-2.25)=1-P(7<-2.25)

P(Z>-2.25)=1-P(Z<-2.25)=1-0.0122=0.9878

06

Final Answer (Part b) 

Hence, the value we getP(Z-2.25)=0.9878.

07

Given information (Part c) 

Use Table A to find the proportion of observations from a standard Normal distribution

z>1.77=?

08

Explanation (Part c) 

Since this is continuous distribution, P(Z1.77)=P(Z>1.77)

Area to the right of 1.77

P(Z>1.77)=1-P(Z<1.77)

P(Z>1.77)=1-P(Z<1.77)=1-0.9616=0.0384

09

Final Answer (Part c)

Hence,P(Z<1.77): in a z-table having an area to the left of z, locate 1.7 in the left most column. Move across the row to the right under column 0.07 and get value 0.9616

P(Z1.77)=0.0384
10

Given information (Part d) 

Use Table A to find the proportion of observations from a standard Normal distribution

-2.25<z<1.77=?

11

Explanation (Part d) 

Area in between -2.25and 1.77

P(-2.25<Z<1.77)=P(Z<1.77)-P(Z<-2.25)

P(-2.25<Z<1.77)=0.9616-0.0122=0.9494

12

Final Answer (Part d)

Hence, we getP(-2.25<Z<1.77)=0.9494.

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