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Chapter 12: Q. 46 (page 792)

Some high school physics students dropped a ball and measured the distance fallen (in centimeters) at various times (in seconds) after its release. If you have studied physics, then you probably know that the theoretical relationship between the variables is distance =490(time)2. A scatterplot of the students’ data showed a clear curved pattern. At 0.68seconds after release, the ball had fallen 220.4centimeters. How much more or less did the ball fall than the theoretical model predicts?

(a) More by 226.576centimeters

(b) More by 6.176centimeters

(c) No more and no less

(d) Less by 226.576centimeters

(e) Less by centimeters

Short Answer

Expert verified

The ball fall than the theoretical model predicts option (e) Less by6.176centimeters.

Step by step solution

01

Explanation

The given value is

x=0.68

y=220.4

distance=490(time)2.

02

Explanation

The given value is

x=0.68

y=220.4

Equation theoretical model

distance =490(time)2

Replace time with 0.68

Distance =490(0.68)2=226.576

The predicted distance is 226.576, while the actual distance is 220.4

226.576-220.4=6.176

Thus the actual distance is 6.176less than the distance predicted by the theoretical model.

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