BMI (5.2) Suppose we select two American young women in this age group at random. Find the probability that at least one of them is classified as underweight. Show your work.

Short Answer

Expert verified

P (at least one of two underweight) = 0.245

Step by step solution

01

Step 1. Given Information

μ=26.8σ=7.4
02

Step 2. Concept used

Using complement rule: P(notA)=1P(A)

03

Step 3. Calculation

P(underweight)=0.131

Complement rule: P(notA)=1P(A)

Applying the complement rule, the likelihood of not being underweight is as follows:P(notunderweight)=1P(underweight)=10.131=0.869=86.9%

Rule of multiplication (if occurrences A and B are unrelated):

P(twonotunderweight)=P(notunderweight)×P(notunderweight)=0.869×0.869=0.755

Use the complement rule once more:

P(atleastoneoftwounderweight)=1P(twonotunderweight)=10.755=0.245

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sampling senators Refer to Exercise 50.

(a) Construct a Venn diagram that models the chance process using events R: is a Republican, and F: is female.

(b) Find P(RF) Interpret this value in context.

(c) Find P(RcFc) Interpret this value in context.

Lotto In the United Kingdom’s Lotto game, a player picks six numbers from 1 to 49 for each ticket. Rosemary bought one ticket for herself and one for each of her four adult children. She had the lottery computer randomly select the six numbers on each ticket. When the six winning numbers were drawn, Rosemary was surprised to find that none of these numbers appeared on any of the five Lotto tickets she had bought. Should she be? Design and carry

out a simulation to answer this question. Follow the four-step process.

During World War II, the British found that the probability that a bomber is lost through enemy action on a mission over occupied Europe was 0.05 Assuming that missions are independent, find the probability that a bomber returned safely from 20 missions.

Liar, liar! Sometimes police use a lie detector (also known as a polygraph) to help determine whether a suspect is telling the truth. A lie detector test isn’t foolproof—sometimes it suggests that a person is lying when they’re actually telling the truth (a “false positive”). Other times, the test says that the suspect is being truthful when the person is actually lying (a “false negative”). For one brand of polygraph machine, the probability of a false positive is 0.08.
(a) Interpret this probability as a long-run relative frequency.
(b) Which is a more serious error in this case: a false positive or a false negative? Justify your answer.

Mac or PC? A recent census at a major university revealed that40% of its students primarily used Macintosh computers (Macs). The rest mainly used

PCs. At the time of the census, 67% of the school’s students were undergraduates. The rest were graduate students. In the census, 23% of respondents were graduate students who said that they used PCs as their

main computers. Suppose we select a student at random from among those who were part of the census.

(a) Assuming that there were 10,000 students in the census, make a two-way table for this chance process.

(b) Construct a Venn diagram to represent this setting.

(c) Consider the event that the randomly selected student is a graduate student who uses a Mac. Write this event in symbolic form using the two events of interest that you chose in (b).

(d) Find the probability of the event described in (c). Explain your method.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free