Color-blind men About$7\%$of men in the United States have some form of red-green color blindness. Suppose we randomly select one U.S. adult male at a time until we find one who is red-green color-blind. How many men would we expect to choose, on average? Design and carry out a simulation to answer this question. Follow the four-step process.

Proportion of men in the United States having some form of red-green color blindness = $0.07$

Random sample size of U.S adults,$n=4$

We have to find the probability that at least one of them is red-green color-blind using the four-step process of designing and carrying out simulation.

We can't foresee the outcomes of a chance process, yet they have a regular distribution over a large number of repetitions. According to the law of large numbers, the fraction of times a specific event occurs in numerous repetitions approaches a single number. The likelihood of a chance outcome is its long-run relative frequency. A probability is a number between $0$ (never happens) and $1$ (happens frequently) (always occurs).

Use two-digit numbers instead of three-digit numbers. Allow the numerals $00$to $06$to symbolize a person who is colorblind in the red-green spectrum. Allow the numbers $07$ to $99$ to represent a person who is not colorblind to red and green. Count how many two-digit numbers you'll need to find the first person with red-green colorblindness. Rep this simulation as many times as you like. Until the first person with red-green colour blindness is located, you will most likely get a result of between $1$ and $20$ needed numbers.