Color-blind men Refer to Exercise $25$. Suppose we randomly select $4$ U.S. adult males. What’s the probability that at least one of them is red-green

color-blind? Design and carry out a simulation to answer this question. Follow the four-step process.

The percentage of men in the United States who suffer from red-green color blindness is $0.07$$n=4$ adults from the United States were randomly selected. Using the four-step design and simulation method, we must determine the likelihood that at least one of them is red-green colorblind.

We can't foresee the outcomes of a chance process, yet they have a regular distribution over a large number of repetitions. According to the law of large numbers, the fraction of times a specific event occurs in numerous repetitions approaches a single number. The likelihood of a chance outcome is its long-run relative frequency. A probability is a number between $0$ (never happens) and $1$ (happens frequently) (always occurs).

We'll use two-digit numbers to obtain the answer. Allow the numerals $00$to $06$to symbolize a person who is colorblind in the red-green spectrum. Allow the numbers $07$to $99$to represent a person who is not colorblind to red and green. Make a set of four two-digit numbers. Count the number of people who are colorblind in the red-green spectrum. You'll most likely get a result of $0$ or $1$ person who is colorblind to red and green.