Use the correct choice from the previous question and these random digits to simulate 10 shots:$8273471490204674751181676553009438314893$How many of these 10 shots are hits? (a) $2$(b) $3$(c) $4$(d) $5$(e) $6$

In the simulation, the number of repetitions is $25$, and the number of shots per repetition is $10$We must calculate the likelihood that a $47$percent shooter will make five or more shots in ten attempts:

We can't foresee the outcomes of a chance process, yet they have a regular distribution over a large number of repetitions. According to the law of large numbers, the fraction of times a specific event occurs in numerous repetitions approaches a single number. The likelihood of a chance outcome is its long-run relative frequency. A probability is a number between $0$(never happens) and $1$(happens frequently) (always occurs).

Two numerals represent one shot; $00$to $46$represents a hit, $47$and $99$represents a miss. We'll start by creating a missed shot using random integers.

Miss = $82,73,47,90,74$

Hits =$14,20,46,11$

As a result, there are four hits out of ten. As a result, option c) is correct.