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Chapter 5: Q 82. (page 330)

Teens online We saw in an earlier example (page 319) that 93% of teenagers are online and that 55% of online teens have posted a profile on a social-networking site. Of online teens with a profile, 76% have placed comments on a friend’s blog. What percent of all teens are online, have a profile, and comment on a friend’s blog? Show your work.

Short Answer

Expert verified

The percentage of all online, have a profile, and comments on a friend’s blog is 38.874%

Step by step solution

01

Step 1. Given Information

93% of teenagers use the internet, and 55% of them have created profiles on social networking sites.

02

Step 2. Concept Used

Conditional probability:P(A∩B)=P(A/B)×P(B)

03

Step 3. Calculation

According to the inquiry, P(college)=93%=0.93

P(profile/online)=55%=0.55P(comments/profile∩online)=76%=0.76

Use the following conditional probability definition:

P(comments∩profile∩online)=P(comments/profile∩online)×P(profile/online)

=P(comments/profile∩online)×P(profile/online)×P(online)=0.76×0.55×0.93=0.38874=38.874%

As a result, the following was obtained:

As a result, the percentage of people who are online, have a profile, and comment on a friend's blog is 38.874%

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