Running a mile A study of 12,000able-bodied male students at the University of Illinois found that their times for the mile run were approximately Normal with mean 7.11minutes and standard deviation 0.74 minute. Choose a student at random from this group and call his time for the mile Y. Find P(Y<6) and interpret the result. Follow the four-step process.

Short Answer

Expert verified

There is a chance of about 6.68% that the student will run a time of less than 6 minutes.

Step by step solution

01

Given Information

μ=7.11

σ=0.74

02

Explanation

The z-score is the value decreased by the mean divided by the standard deviation:

z=x-μσ=6-7.110.74-1.50

Determine the corresponding probability using the normal probability table in the appendix:

P(X<6)=P(Z<-1.50)=0.0668=6.68%

There is a chance of about 6.68% that the student will run a time of less than 6 minutes.

03

Final Answer

The probability ofP(X<6)=0.0668.

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