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Chapter 9: Q 1.2. (page 570)

For the job satisfaction study described in Section 9.1, the hypotheses are

H0∶μ=0Ha:μ≠0

where μis the mean difference in job satisfaction scores (self-paced - machine-paced) in the population of assembly-line workers at the company? Data from a random sample of 18workers gave x=17andsx=60

Use Table B to find the P-value. What conclusion would you draw?

Short Answer

Expert verified

The P -value is 0.221

Step by step solution

01

Given information

Sample mean (x)=17

Sample size (n)=18

Sample standard deviation (s)=60

Test statistic (t)=1.273

02

Concept

The test statistic is computed as: t=x⏜−μsn

x = Sample mean

μ = Population mean

n = Sample size

s = Sample standard deviation

03

Calculation

The degree of freedom is computed as:

Df=n−1=18−1=17

The P-value can be calculated as:

P−value=2×P(t>|1.2)=0.221

P is bigger than the significance level in this case (0.221).(0.05). The null hypothesis is rejected in this case.

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Most popular questions from this chapter

You are thinking about opening a restaurant and are searching for a good location. From the research you have done, you know that the mean income of those living near the restaurant must be over $85,000 to support the type of upscale restaurant you wish to open. You decide to take a simple random sample of 50 people living near one potential location. Based on the mean income of this sample, you will decide whether to open a restaurant there.8

(a) State appropriate null and alternative hypotheses. Be sure to define your parameter.

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(b)zrequires that you know the population standard deviation σ.

(c) zrequires you to regard your data as an SRS from the population.

(d) zapplies only if the population distribution is perfectly Normal.

(e) zcan be used only for confidence intervals.

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