Attitudes In the study of older students’ attitudes from Exercise 3, the sample mean SSHA score was 125.7 and the sample standard deviation was 29.8. A significance test yields a P-value of 0.0101.

(a) Interpret the P-value in context.

(b) What conclusion would you make if α=0.05? If data-custom-editor="chemistry" α=0.01? Justify your answer.

Short Answer

Expert verified

a. When the population mean is115, there is a 1.01%chance of getting a sample mean of 125.7

b. Enough convincing evidence against the null hypothesis when α=0.05and not enough convincing evidence against the null hypothesis whenα=0.01

Step by step solution

01

Part (a) Step 1: Given Information

Sample mean = 125.7

Sample standard deviation = 29.8

P-value =0.0101

02

Part (a) Step 2: Explanation

The sample mean x-= 125.7

standard deviation σ=29.8

P-value = role="math" localid="1654319413192" 0.0101=1.01%

Calculating the null and alternative hypotheses,

Ho:μ=115Ha:μ>115

Hence when the population mean is115, there is a 1.01%chance of getting a sample mean of 125.7

03

Part (b) Step 1: Given Information

Sample mean =125.7

Sample standard deviation =29.8

P-value =0.0101=1.01%

04

Part (b) Step 2: Explanation

The p-value = 0.0101

When α=0.05

The p-value is less than α=0.005

The null hypothesis is rejected

When α=0.01α=0.01

The p-value is greater thanα=0.01

The null hypothesis is not rejected

Hence there is enough convincing evidence against the null hypothesis when α=0.05and not enough convincing evidence against the null hypothesis whenα=0.01

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