A random sample of $100$likely voters in a small city produced $59$voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis $H_0:p=0.5$versus the alternative hypothesis $H_a:p=0.5$is

$\text{(a)}z=\frac{0.59-0.5}{\sqrt{\frac{0.59(0.41)}{100}}}$

(b). $z=\frac{0.59-0.5}{\sqrt{\frac{0.5(0.5)}{100}}}$

(c). $z=\frac{0.5-0.59}{\sqrt{\frac{0.59(0.41)}{100}}}$

(d). $z=\frac{0.5-0.59}{\sqrt{\frac{0.5(0.5)}{100}}}$

(e).$t=\frac{0.59-0.5}{\sqrt{\frac{0.5(0.5)}{100}}}$

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