The composition of the earth’s atmosphere may have changed over time. To try to discover the nature of the atmosphere long ago, we can examine the gas in bubbles inside ancient amber. Amber is tree resin that has hardened and been trapped in rocks. The gas in bubbles within amber should be a sample of the atmosphere at the time the amber was formed. Measurements on 9 specimens of amber from the late Cretaceous era (75 to 95 million years ago) give these percent of nitrogen:

63.4 65.0 64.4 63.3 54.8 64.5 60.8 49.1 51.0

Explain why we should not carry out a one-sample t test in this setting.

Short Answer

Expert verified

The selection of the sample is done through a simple random technique hence we should not carry out a one-sample t test in this setting.

Step by step solution

01

Introduction

A test statistic is a statistic utilized in statistical hypothesis testing. A hypothesis test is typically specified as far as a test statistic, considered as a numerical synopsis of an informational collection that decreases the information to one worth that can be utilized to play out the hypothesis test.

02

Explanation

Given,

63.4    65.0    64.4    63.3    54.8    64.5    60.8    49.1    51.0

We cannot carry out a one-sample t-test in this setting as a selection of the sample is done through a simple random technique and the sample size is 9which is less than 30. Hence the normality assumption is not satisfied.

Hence the selection of the sample is done through a simple random technique and we should not carry out a one-sample t test in this setting.

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Most popular questions from this chapter

A random sample of 100likely voters in a small city produced 59voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis H0:p=0.5versus the alternative hypothesis Ha:p=0.5is

(a)z=0.59-0.50.59(0.41)100

(b). z=0.59-0.50.5(0.5)100

(c). z=0.5-0.590.59(0.41)100

(d). z=0.5-0.590.5(0.5)100

(e).t=0.59-0.50.5(0.5)100

Two-sided test The one-sample t statistic from a sample of n=25observations for the two-sided test of H0:μ=64;Ha:μ64has the value t=-1.12.

(a) Find the P-value for this test using (i) Table Band (ii) your calculator. What conclusion would you draw at the 5%significance level? At the 1%significance level?

(b) Redo part (a) using an alternative hypothesis of Ha:μ<64.

Your company markets a computerized device for detecting high blood pressure. The device measures an individual’s blood pressure once per hour at a randomly selected time throughout a 12-hour period. Then it calculates the mean systolic (top number) pressure for the sample of measurements. Based on the sample results, the device determines whether there is significant evidence that the individual’s actual mean systolic pressure is greater than 130. If so, it recommends that the person seek medical attention.

(a) State appropriate null and alternative hypotheses in this setting. Be sure to define your parameter.

(b) Describe a Type I and a Type II error, and explain the consequences of each.

(c) The blood pressure device can be adjusted to decrease one error probability at the cost of an increase in the other error probability. Which error probability would you choose to make smaller, and why?

Normal body temperature (8.3) Check that the conditions are met for performing inference about the mean body temperature in the population of interest.

You are testing H0:μ=10against Hα:μ10based on an SRS of 15tobservations from a Normal population. What values of the statistic are statistically significant at theα=0.005level?

(a) t>3.326

(b) t>3.286

(c) t>2.977

(d) t<-3.326ort>3.326

(c)t<-3.286ort>3.286

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