Does listening to music while studying help or hinder students’ learning? Two AP Statistics students designed an experiment to find out. They selected a random sample of 30students from their medium-sized high school to participate. Each subject was given10minutes to memorize two different lists of 20words, once while listening to music and once in silence. The order of the two word lists was determined at random; so was the order of the treatments. A boxplot of the differences in the number of words recalled (music- silent) is shown below, along with some Minitab output from a one-sample t test. Perform a complete analysis of the students’ data. Include a confidence interval.

Short Answer

Expert verified

The 95%confidence interval is(1.561,0.298).

Step by step solution

01

Given information

Given in the question that, Two AP Statistics students designed an experiment to find out. They selected a random sample of 30students from their medium-sized high school to participate. Each subject was given 10minutes to memorize two different lists of 20words, once while listening to music and once in silence. The order of the two word lists was determined at random; so was the order of the treatments. A boxplot of the differences in the number of words recalled (music -silent) is shown below, along with some Minitab output from a one-sample t test. Perform a complete analysis of the students’ data. Include a confidence interval

02

Explanation

Given

The boxplot and output are

The formula to compute the t-confidence interval for population mean is:

Cl=x¯±ta/2df×sn

03

Step 3:Alternative hypothesis  

The null and the alternative hypothesis are:

H0:μ=0Ha:μ0

From the provided output, the P-value is less than the significance level (0.05). Thus, the null hypothesis is rejected and it implies that there is enough evidence to agree with the provided claim at 5%significance level.

Here, the degree of freedom is:

Df=n-1=30-1=29

The confidence interval using Ti-83output is:

Thus, the 95%confidence interval is(1.561,0.298)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Normal body temperature (8.2) If "normal" body temperature really is 98.6F, we would expect the proportion pof all healthy 18- to 40 -year-olds who have body temperatures less than this value to be 0.5. Construct and interpret a 95% confidence interval for p. What conclusion would you draw?

Asked to explain the meaning of “statistically significant at the A 0.05 level,” a

student says, “This means that the probability that the null hypothesis is true is less than 0.05.” Is this explanation correct? Why or why not?

After checking that conditions are met, you perform a significance test of H0:μ=1versus Hα:μ1. You obtain a Pvalue of 0.022. Which of the following is true?

(a) A95%confidence interval for μwill include the value 1

(b) A 95%confidence interval forμwill include the value 0.

(c) A99% confidence interval forμwill include the value 1

(d) A 99%confidence interval for μwill include the value 0

(e) None of these is necessarily true.

A Gallup Poll report on a national survey of 1028 teenagers revealed that 72% of teens said they seldom or never argue with their friends. Yvonne wonders whether this national result would be true in her large high school. So she surveys a

a random sample of 150 students at her school.

Heat through the glass How well materials conduct heat matters when designing houses, for example. Conductivity is measured in terms of watts of heat power transmitted per square meter of surface per degree Celsius of temperature difference on the two sides of the material. In these units, glass has conductivity about 1. The National Institute of Standards and Technology provides exact data on properties of materials. Here are measurements of the heat conductivity of 11randomly selected pieces of a particular type of glass:

1.111.071.111.071.121.081.081.181.181.181.12

Is there convincing evidence that the conductivity of this type of glass is greater than 1? Carry out a test to help you answer this question.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free