Let X represent the outcome when a fair six-sided die is rolled. For this random variable, μX=3.5and σX=1.71. If the die is rolled 100 times, what is the approximate probability that the sum is at least 375?

a. 0.0000

b.0.0017

c.0.0721

d.0.4420

e.0.9279

Short Answer

Expert verified

The probability is 0.0721

Step by step solution

01

Given Information

We have to find the probability that sum is at least 375.

02

Simplification

Population mean (μx)=3.5

Population standard deviation(σx)=1.71

Sample size (n)=100

The mean can be calculated as follows:

x-=375100=3.75

The likelihood that the sum is at least 375can be computed as follows:

P(x-3.75)=Pxμσn3.753.51.71100=P(Z1.47)=1P(Z1.47)=0.0721

Thus, the required probability is0.0721.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

On your mark In track, sprinters typically use starting blocks because they think it will help them run a faster race. To test this belief, an experiment was designed where each sprinter on a track team ran a 50-meter dash two times, once using starting blocks and once with a standing start. The order of the two different types of starts was determined at random for each sprinter. The times (in seconds) for 8 different sprinters are shown in the table.

a. Make a dotplot of the difference (Standing - Blocks) in 50-meter run time for each sprinter. What does the graph suggest about whether starting blocks are helpful?

b. Calculate the mean difference and the standard deviation of the differences. Explain why the mean difference gives some evidence that starting blocks are helpful.

c. Do the data provide convincing evidence that sprinters like these run a faster race when using starting blocks, on average?

d. Construct and interpret a 90%confidence interval for the true mean difference. Explain how the confidence interval gives more information than the test in part (b).

There are two common methods for measuring the concentration of a pollutant in fish tissue. Do the two methods differ, on average? You apply both methods to each fish in a random sample of 18carp and use

a. the paired t test for μdiff3051526=0.200=20.0%μdiff.

b. the one-sample z test for p.

c. the two-sample t test for μ1-μ23051526=0.200=20.0%μ1-μ2.

d. the two-sample z test for p1-p23051526=0.200=20.0%p1-p2.

e. none of these.

Don’t drink the water!The movie A Civil Action (1998) tells the story of a

major legal battle that took place in the small town of Woburn, Massachusetts. A town well that supplied water to east Woburn residents was contaminated by industrial chemicals. During the period that residents drank water from this well, 16of 414babies born had birth defects. On the west side of Woburn, 3of 228babies born during the same time period had birth defects. Let p1be

the true proportion of all babies born with birth defects in west Woburn and p2be the true proportion of all babies born with birth defects in east Woburn. Check if the conditions for calculating a confidence interval forp1-p2are met.

Friday the 13th Do people behave differently on Friday the13th? Researchers collected data on the number of shoppers at a random sample of 45grocery stores on Friday the 6thand Friday the 13thin the same month. Then they calculated the difference (subtracting in the order6thminus13th ) in the number of shoppers at each store on these 2days. The mean difference is -46.5and the standard deviation of the differences is 178.0.

a. If the result of this study is statistically significant, can you conclude that the difference in shopping behavior is due to the effect of Friday the 13thon people’s behavior? Why or why not?

b. Do these data provide convincing evidence at theα=0.05level that the number of shoppers at grocery stores on these 2days differs, on average?

c. Based on your conclusion in part (a), which type of error—a Type I error or a Type II error—could you have made? Explain your answer.

Researchers suspect that Variety A tomato plants have a different average yield than Variety B tomato plants. To find out, researchers randomly select10Variety A and10Variety B tomato plants. Then the researchers divide in half each of10small plots of land in different locations. For each plot, a coin toss determines which half of the plot gets a Variety A plant; a Variety B plant goes in the other half. After harvest, they compare the yield in pounds for the plants at each location. The10differences (Variety A − Variety B) in yield are recorded. A graph of the differences looks roughly symmetric and single-peaked with no outliers. The mean difference is x-A-B=0.343051526=0.200=20%x-A-B=0.34and the standard deviation of the differences is s A-B=0.833051526=0.200=20%=sA-B=0.83.Let μA-B=3051526=0.200=20%μA−B = the true mean difference (Variety A − Variety B) in yield for tomato plants of these two varieties.

A 95% confidence interval forμA-B3051526=0.200=20%μA-Bis given by

a. 0.34±1.96(0.83)3051526=0.200=20%0.34±1.96(0.83)

b.0.34±1.96(0.8310)3051526=0.200=20%0.34±1.96(0.8310)

c. 0.34±1.812(0.8310)3051526=0.200=20%0.34±1.812(0.8310)

d. 0.34±2.262(0.83)3051526=0.200=20%0.34±2.262(0.83)

e.0.34±2.262(0.8310)3051526=0.200=20%0.34±2.262(0.8310)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free