Treating AIDS The drug AZT was the first drug that seemed effective in delaying

the onset of AIDS. Evidence for AZT’s effectiveness came from a large randomized

comparative experiment. The subjects were 870volunteers who were infected with HIV,

the virus that causes AIDS, but did not yet have AIDS. The study assigned 435of the

subjects at random to take 500milligrams of AZT each day and another 435to take a

placebo. At the end of the study, 38of the placebo subjects and 17of the AZT subjects

had developed AIDS.

a. Do the data provide convincing evidence at the α=0.05level that taking AZT lowers the proportion of infected people like the ones in this study

who will develop AIDS in a given period of time?

b. Describe a Type I error and a Type II error in this setting and give a consequence of

each error.

Short Answer

Expert verified

(a)Yes,the data provide convincing evidence at the α=0.05level that taking AZT lowers the proportion of infected people.

(b)Type I error : This error occurs when our null hypotheses is true and we reject our null hypotheses.

consequence of Type I error :Our decision is wrong.

Type II error : This error occurs when our null hypotheses is false and we accept our null hypotheses.

consequence of Type II error :Our decision is wrong.

Step by step solution

01

Part (a) Step 1:Given Information

We have been given that,

Number of subjects assigned to take AZT each day(n1)=435

Number of AZT subjects who had developed AIDS (r1)=17

Number of subjects assigned to take placebo each day (n2) =435

Number of placebo subjects who had developed AIDS (r2)=38

02

Part (a) Step 2:Explanation

P1=Observed proportion in first sample

P1= r1n1=17436=0.03

P2=Observed proportion in second sample

P2=r2n2=38435=0.08

p1=proportion in first population

p2=proportion in second population

Observed value of difference in proportions=P1-P2

Expected value of difference in proportions=p1-p2=0

p=(r1+r2)/n1+n2

p=17+38435+435=0.06

q=1-p=1-0.06=0.94

Standard Deviation=p×q×(1n1+1n2)=0.06×0.94×(1435+1435)=0.016

Null hypotheses: AZT do not lowers the proportion of infected people

Alternative hypotheses: AZT lowers the proportion of infected people

localid="1654269083875" Z=P1-P2-0p×q×(1n1+1n2)

localid="1654269118341" z=0.03-0.08-00.016

localid="1654269502461" z=-3.125

Tabulated value at α=0.05level of significance =±1.96

Since zcal>ztab

Null hypotheses is rejected.

Conclusion:AZT lowers the proportion of infected people

03

Part (b) Step 1:Given Information

We have to describe a Type I error and a Type II error

04

Part (b) Step 2:Explanation

Type I error : This error occurs when our null hypotheses is true and we reject our null hypotheses.

consequence of Type I error :Our decision is wrong.

Type II error : This error occurs when our null hypotheses is false and we accept our null hypotheses.

consequence of Type II error :Our decision is wrong.

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