Quiz grades Refer to Exercise 87.

(a) Find the median of Joey’s first 14 quiz grades.

(b) Find the median of Joey’s quiz grades after his unexcused absence. Explain why the 0 quiz grade does not have much effect on the median.

Short Answer

Expert verified

Part (a) 85

Part (b) 84, resistant property of the median

Step by step solution

01

Part (a) Step 1. Given information.

The given grades are:

02

Part (a) step 1. Find the median of Joey’s first 14 quiz grades.

Arrange the given grades from smallest to largest:

74, 75, 76, 78, 80, 82, 84, 86, 87, 90, 91, 93, 96, 98

As we know that median is the middle value of a data set. As the given set is even, the median will be the average of the two middle values (7th and 8th) of this sorted data:

M=84+862=1702=85

03

Part (b) Step 1.  Find the median of Joey’s quiz grades after his unexcused absence.

86, 84, 91, 75, 78, 80, 74, 87, 76, 96, 82, 90, 98, 93, 0

Arrange the given grades from smallest to largest:

0, 74, 75, 76, 78, 80, 82, 84, 86, 87, 90, 91, 93, 96, 98

Median is:

M=84

Median is a resistant measure of center, the reason is median is not strongly influenced by the extreme observations. Therefore, the resistant property of the median is followed here.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free