Aw, nuts! A company claims that each batch of its deluxe mixed nuts

contains 52% cashews, 27%almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data.

a. State appropriate hypotheses for performing a test of the company’s claim.

b. Calculate the expected count for each type of nut.

c. Calculate the value of the chi-square test statistic.

Short Answer

Expert verified

Part (a)H0:pc=52%,pa=27%,pm=13%,pb=8%,Ha:Atleastoneofthepisisincorrect.

Part (b)

Type of nutsCountFrequencyExpected
Cashew8352%78
Almond2927%40.5
Macadamia2013%19.5
Brazil188%12
Total150100%150

Part (c) The chi-square test statistic =6.60

Step by step solution

01

Part (a) Step 1: Given information

Type of nutCountFrequency
Cashew8352%
Almond2927%
Macadamia2013%
Brazil188%
02

Part (a) Step 2: Explanation

The null and alternative hypotheses:

H0:pc=52%,pa=27%,pm=13%,pb=8%,Ha:Atleastoneofthepisisincorrect.

03

Part (b) Step 1: Explanation

Expectedvalue=n×frequency

Where, n=150

Expected count will be:

Type of nutsCountFrequencyExpected
Cashew8352%78
Almond2927%40.5
Macadamia2013%19.5
Brazil188%12
Total150100%150
04

Part (c) Step 1: Explanation

Using excel

Type of nutsObservedExpectedO-E
O-E2/E
% of chisq
Cashew8378.0005.0005.0004.86
Almond2940.500-11.5003.26549.49
Macadamia2019.5000.5000.0130.19
Brazil1812.0006.0003.00045.46

150150.0000.0006.599100.00







6.60chi-square



3Df



.0858p-value


Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which test? Determine which chi-square test is appropriate in each of the following settings. Explain your reasoning.

a. With many babies being delivered by planned cesarean section, Mrs. McDonald’s statistics class hypothesized that there would be fewer younger people born on the weekend. To investigate, they selected a random sample of people born before1980 and a separate random sample of people born after1993. In addition to year of birth, they also recorded the day of the week on which each person was born.

b. Are younger people more likely to be vegan/vegetarian? To investigate, the Pew Research Center asked a random sample of 1480 U.S. adults for their age and whether or not they are vegan/vegetarian.

Do students who read more books for pleasure tend to earn higher grades in English? The boxplots show data from a simple random sample of 79 students at a large high school. Students were classified as light readers if they read fewer than 3 books for pleasure per year. Otherwise, they were classified as heavy readers. Each student’s average English grade for the previous two

marking periods was converted to a GPA scale, where A=4.0,A=3.7,B+=3.3

and so on.

Gummy bears Courtney and Lexi wondered if the distribution of color was

the same for name-brand gummy bears (Haribo Gold) and store-brand gummy bears

(Great Value). To investigate, they randomly selected bags of each type and counted the

number of gummy bears of each color.

Do these data provide convincing evidence that the distributions of color differ for name-

brand gummy bears and store-brand gummy bears?

Here are the data:

When analyzing survey results from a two-way table, the main distinction between a test for independence and a test for homogeneity is

a. how the degrees of freedom are calculated.

b. how the expected counts are calculated.

c. the number of samples obtained.

d. the number of rows in the two-way table.

e. the number of columns in the two-way table.

Cocaine addicts need cocaine to feel any pleasure, so perhaps giving them an antidepressant drug will help. A 3-year study with 72chronic cocaine users compared an antidepressant drug called desipramine with lithium (a standard drug to treat cocaine addiction) and a placebo. One-third of the subjects were randomly assigned to receive each treatment. At the end of the study, researchers recorded whether or not the subjects relapsed. Which of the following conditions must be satisfied to perform the appropriate chi-square test using the data from this study?

I. The population distribution is approximately Normal.

II. The treatments were randomly assigned.

III. The observed counts are all at least 5.

a. I only

b. II only

c. III only

d. II and III

e. I, II, and III

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free