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Chapter 11: Q. 59 (page 758)

When analyzing survey results from a two-way table, the main distinction between a test for independence and a test for homogeneity is

a. how the degrees of freedom are calculated.

b. how the expected counts are calculated.

c. the number of samples obtained.

d. the number of rows in the two-way table.

e. the number of columns in the two-way table.

Short Answer

Expert verified

Option C) is correct that is the number of samples obtained.

Step by step solution

01

Given Information

We have to identify correct answer when analyzing survey results from a two way table, the main distinction between a test for independence and a test for homogeneity

02

Simplification

The sole difference between homogeneity and independence tests is the number of samples obtained.

Thus, Option C) is correct.

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Most popular questions from this chapter

Roulette Refer to Exercise 2.

a. Confirm that the expected counts are large enough to use a chi-square distribution to calculate the P-value. What degrees of freedom should you use?

b. Use Table C to find the P-value. Then use your calculator’s χ2 cdf command.

c. What conclusion would you draw about whether or not the roulette wheel is operating correctly?

Is astrology scientific? The General Social Survey (GSS) asked a random sample of adults their opinion about whether astrology is very scientific, sort of scientific, or not at all scientific. Here is a two-way table of counts for people in the sample who had three levels of higher education:

a. State appropriate hypotheses for performing a chi-square test for independence in this setting.

b. Compute the expected counts assuming that H0is true.

c. Calculate the chi-square test statistic, df, and P-value.

d. What conclusion would you draw?

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Here are the data:

Computer software was used to analyze the data. The output included the value X2=0.435

Which of the following is the appropriate degrees of freedom for the X2test?

a. 1

b. 2

c. 3

d. 4

e. 5

A random sample of traffic tickets given to motorists in a large city is examined. The tickets are classified according to the race or ethnicity of the driver. The results are summarized in the following table.

The proportion of this city's population in each of the racial/ethnic categories listed is as follows.

We wish to test H0: The racial/ethnic distribution of traffic tickets in the city is the same as the racial/ethnic distribution of the city's population.

Assuming H0is true, what is the expected number of Hispanic drivers who would receive a ticket?

a.8

b.10.36

c.11

d.11.84

e.12

Do students who read more books for pleasure tend to earn higher grades in English? The boxplots show data from a simple random sample of 79 students at a large high school. Students were classified as light readers if they read fewer than 3 books for pleasure per year. Otherwise, they were classified as heavy readers. Each student’s average English grade for the previous two

marking periods was converted to a GPA scale, where A=4.0, A−=3.7, B+=3.3

Reading and grades (3.2) The scatterplot shows the number of books read and the English grade for all 79 students in the study. The least-squares regression line y^=3.42+0.024x has been added to the graph.

a. Interpret the slope and y intercept.

b. The student who reported reading 17 books for pleasure had an English GPA of 2.85. Calculate and interpret this student’s residual.

c. For this linear model, r2=0.083 Interpret this value.
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