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Chapter 11: Q 8. (page 716)

No chi-square The principal in Exercise 7 also asked the random sample of students to record whether they did all of the homework that was assigned on each of the five school days that week. Here are the data:

Short Answer

Expert verified

Because the observations are not independent, a chi-square test for goodness of fit is not appropriate.

Step by step solution

01

Given information

02

Explanation

The observations must be independent in order to use the chi-square test for goodness of fit. Because most kids will have the same teachers, independent observations are not possible. As a result, a chi-square test for goodness of fit would be inappropriate.

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Most popular questions from this chapter

Preventing strokes Aspirin prevents blood from clotting and so helps prevent strokes.

The Second European Stroke Prevention Study asked whether adding another anticlotting

drug named dipyridamole would be more effective for patients who had already had a

stroke. Here are the data on strokes during the two years of the study

a. Summarize these data in a two-way table.

b. Do the data provide convincing evidence of a difference in the effectiveness of the four

treatments at theα=0.05significance level?

Do students who read more books for pleasure tend to earn higher grades in English? The boxplots show data from a simple random sample of 79 students at a large high school. Students were classified as light readers if they read fewer than 3 books for pleasure per year. Otherwise, they were classified as heavy readers. Each student’s average English grade for the previous two

marking periods was converted to a GPA scale, where A=4.0,A−=3.7,B+=3.3

and so on.

The manager of a high school cafeteria is planning to offer several new types of food for student lunches in the new school year. She wants to know if each type of food will be equally popular so she can start ordering supplies and making other plans. To find out, she selects a random sample of 100students and asks them, “Which type of food do you prefer: Ramen, tacos, pizza, or hamburgers?” Here are her data:

The P-value for a chi-square test for goodness of fit is 0.0129. Which of the following is the most appropriate conclusion at a significance level of 0.05?

a. Because 0.0129 is less than α=0.05 reject H0 . There is convincing evidence that the food choices are equally popular.

b. Because 0.0129 is less than α=0.05 reject H0 There is not convincing

evidence that the food choices are equally popular.

c. Because 0.0129 is less than α=0.05 reject H0 . There is convincing evidence that the food choices are not equally popular.

d. Because 0.0129 is less than α=0.05 fail to reject H0 There is not convincing evidence that the food choices are equally popular.

e. Because 0.0129 is less than α=0.05 fail to reject H0 There is convincing

evidence that the food choices are equally popular.

A random sample of traffic tickets given to motorists in a large city is examined. The tickets are classified according to the race or ethnicity of the driver. The results are summarized in the following table.

The proportion of this city's population in each of the racial/ethnic categories listed is as follows.

We wish to test H0: The racial/ethnic distribution of traffic tickets in the city is the same as the racial/ethnic distribution of the city's population.

Assuming H0is true, what is the expected number of Hispanic drivers who would receive a ticket?

a.8

b.10.36

c.11

d.11.84

e.12

Last candy Refer to Exercises 27 and 29.

a. Verify that the conditions for inference are met.

b. Use Table C to find the P-value. Then use your calculator’s χ2 cdf command.

c. Interpret the P-value from the calculator.

d. What conclusion would you draw using α=0.01?
See all solutions

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