Long jump Refer to Exercise 21 Suppose that the corrected long-jump

distances are converted from centimeters to meters (note that 100cm=1m ).

a. What shape would the resulting distribution have? Explain your answer.

b. Find the mean of the distribution of corrected long-jump distance in meters.

c. Find the standard deviation of the distribution of corrected long-jump distance in meters.

Short Answer

Expert verified

Part (a) The distribution is roughly symmetric along with a single peak.

Part (b) Mean of the distribution of the corrected long jump distance is 5.573m

Part (c) Standard deviation of the distribution of the corrected long jump distance is 0.04713m

Step by step solution

01

Part (a) Step 1: Given information

100cm=1m

xN=557.3cm

To convert the corrected long jump distances from centimetres to metres, divide each centimetre number by 100

02

Part (a) Step 2: Explanation

The geometry of the corrected long-jump distances in centimetres distribution was discovered to be a fairly symmetric distribution with a single peak.

When every value in the data is split by 100, the structure of the distribution remains unchanged because the associations between each data pair remain unchanged.

As a result, the shape of the corrected long-jump distances in metres distribution is also an approximately symmetric distribution with a single peak in this example.

03

Part (b) Step 1: Calculation

To convert the corrected long-jump distances from centimetres to metres, divide each centimetre number by 100

Because the mean is the measure of the centre, when we divide every data value by 100we must likewise divide the centre of the distribution by 100

In the previous problem, we learned that the mean of the corrected long-jump distance distribution was 557.3cmTo convert the mean of the adjusted long-jump distance distribution from centimetres to metres, multiply the mean in centimetres by 100

xN=557.3100=5.573m

Thus,

The distribution of corrected long-jump distance in metres has a mean of5.573m

04

Part (c) Step 1: Calculation

We discovered that the standard deviation of the corrected long-jump distance distribution was 4.713mWe must divide the standard deviation in centimetres by 100to transform the standard deviation of the distribution of corrected long-jump distances from centimetres to metres.

SDN=4.713100=0.04713m

Thus,

The standard deviation of the adjusted long jump distance distribution in metres is0.0473m

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Outliers The percent of the observations that are classified as outliers by the 1.5×IQRrule is the same in any Normal distribution. What is this percent? Show your method clearly.

The army reports that the distribution of head circumference among male soldiers is approximately Normal with mean of 22.8inches and standard deviation 1.1inches.

(a) A male soldier whose head circumference is 23.9-inches would be at what percentile? Show your method clearly.

(b) The army’s helmet supplier regularly stocks helmets that fit male soldiers with head circumferences between 20and 26inches. Anyone with a head circumference outside that interval requires a customized helmet order. What percent of male soldiers require custom helmets? Show your work, including a well-labeled sketch of a Normal curve.

(c) Find the interquartile range for the distribution of head circumference among male soldiers. Show your method clearly.

Blood pressure Refer to Exercise 56 According to the same health information website, diastolic blood pressure between 80 and 90 indicates borderline high blood pressure. About what percent of adults have borderline high blood pressure?

Big sharks Refer to Exercise 76

a. Use your calculator to make a Normal probability plot of the data. Sketch this graph on your paper.

b. What does the graph in part (a) imply about whether the distribution of shark length is approximately Normal? Explain.

Potato chips Refer to Exercise 47 About what percent of 9-ounce bags of

this brand of potato chips weigh less than the advertised 9 ounces? Is this likely to pose a problem for the company that produces these chips?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free