Union and intersection Suppose A and B are two events such that P (A)=0.3, P (B)=0.4, and

P (A∪B)=0.58. Find P (A∩B).

Short Answer

Expert verified

The P(AB)is0.12.

Step by step solution

01

Given Information

We are given the values of P (A)=0.3,P (B)=0.4, PAB=0.58and we have to find out the value of PAB.

02

Explanation

Apply the union rule of probability,

which states thatP(AB)=PA+PB-PAB

P(A)=0.3,P(B)=0.4,P(AB)=0.58.

Put these valuesinto union rules.

We getPAB=0.4+0.3-0.58=0.12

Hence, the value of the probability of intersection between A and B is0.12.

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