Housing in San José How do rented housing units differ from units occupied by their owners? Here are the distributions of the number of rooms for owner-occupied units and renter-occupied units in San José, California:

Let X= the number of rooms in a randomly selected owner-occupied unit and Y = the number of rooms in a randomly chosen renter-occupied unit.

(a) Here are histograms comparing the probability distributions of X and Y. Describe any differences you observe.

(b) Find the expected number of rooms for both types of housing unit. Explain why this difference makes sense.

(c) The standard deviations of the two random variables are σX=1.640and σY=1.308. Explain why this difference makes sense.

Short Answer

Expert verified

Part (a) Both distributions have a minor rightward bias.

In owner-occupied homes, the most common number of rooms is 6, whereas, in renter-occupied units, the most common number of rooms is 4.

The number of rooms in owner-occupied units is more evenly distributed than the number of rooms in renter-occupied homes. There are no outliers in either distribution.

Part (b) Owned: 6.284 and Rented: 4.187

Part (c) The standard deviations confirm that the histogram of owner-occupied apartments is wider than the histogram of renter-occupied units.

Step by step solution

01

Part (a) Step 1. Given information.

The given information is:

02

Part (a) Step 2. Describe any differences that you observe. in the given histograms X and Y.

The highest bars in the histograms are to the left, while a tail of lower bars is to the right, both distributions are skewed to the right.

Because the tallest bar in the histogram for owner-occupied units is 6, the most common number of rooms in owner-occupied homes is 6. Because the highest bar in the histogram for rented-occupied apartments is 4, the most common number of rooms in renter-occupied units is four.


Because the width of the histogram for owner-occupied apartments is wider than the width of the histogram for renter-occupied units, the spread of the number of rooms in owner-occupied units is greater than the spread of the number of rooms in renter-occupied homes.


There are no outliers in either distribution since there are no gaps in the histogram.

03

Part (b) Step 1. Find the expected value of each variable.

Mean of Owned:

μ=xPX=x=1×0.003+2×0.002+3×0.023+4×0.104+5×0.210+6×0.224+7×0.197+8×0.149+9×0.053+10×0.035=6.284

Mean of Rented:

μ=xPX=x=1×0.008+2×0.027+3×0.287+4×0.363+5×0.164+6×0.093+7×0.039+8×0.013+9×0.003+10×0.003=4.187

Because the width of the histogram for owner-occupied apartments is wider than the width of the histogram for renter-occupied units, the spread of the number of rooms in owner-occupied units is greater than the spread of the number of rooms in renter-occupied homes.

04

Part (c) step 1. Differences in standard deviation.

The histogram of owner-occupied units is larger, we inferred that the spread of the owner-occupied distribution was greater than the spread of the renter-occupied distribution in section (a).

The standard deviations reflect this, with the standard deviation of "owned" being higher than the standard deviation of "rented".

The standard deviations confirm that the histogram of owner-occupied apartments is wider than the histogram of renter-occupied units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Baby elk Biologists estimate that a randomly selected baby elk has a 44 % chance of surviving to adulthood. Assume this estimate is correct. Suppose researchers choose 7 baby elk at random to monitor. Let X= the number that survive to adulthood.

Life insurance A life insurance company sells a term insurance policy to 21-year-old males that pays \(100,000 if the insured dies within the next 5 years. The probability that a randomly chosen male will die each year can be found in mortality tables. The company collects a premium of \)250 each year as payment for the insurance. The amount Y that the company earns on a randomly selected policy of this type is \(250 per year, less the \)100,000 that it must pay if the insured dies. Here is the probability distribution of Y:

(a) Explain why the company suffers a loss of $98,750 on such a policy if a client dies at age 25.

(b) Calculate the expected value of Y. Explain what this result means for the insurance company.

(c) Calculate the standard deviation of Y. Explain what this result means for the insurance company.

Taking the train Refer to Exercise 80 . Would you be surprised if the train arrived on time on fewer than 4 days? Calculate an appropriate probability to support your answer.

Ms. Hall gave her class a 10-question multiple-choice quiz.

Let X=the number of questions that a randomly selected student in the class answered correctly. The computer output gives information about the probability distribution of X. To determine each student’s grade on the quiz (out of 100), Ms. Hall will multiply his or her number of correct answers by 5and then add 50.Let G=the grade of a randomly chosen student in the class.

Easy quiz

a. Find the median of G.

b. Find the interquartile range (IQR) of G.

Electronic circuit The design of an electronic circuit for a toaster calls for a 100ohm resistor and a 250-ohm resistor connected in series so that their resistances add. The components used are not perfectly uniform, so that the actual resistances vary independently according to Normal distributions. The resistance of 100-ohm resistors has mean 100ohms and standard deviation 2.5ohms, while that of 250-ohm resistors has mean 250 ohms and standard deviation 2.8ohms.

(a) What is the distribution of the total resistance of the two components in series?

(b) What is the probability that the total resistance

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free