Bull's-eye! Lawrence likes to shoot a bow and arrow in his free time. On any shot, he has about a 10%chance of hitting the bull's-eye. As a challenge one day, Lawrence decides to keep shooting until he gets a bull's-eye. Let Y=the number of shots he takes.

Short Answer

Expert verified

The given statement is not correct, Y cannot be stated to follow the binomial distribution.

Step by step solution

01

Given Information

The likelihood of success p=10%=0.10

02

According to the given question

The random variable Y satisfies the following requirements.

1. The likelihood of success, i.e., the chance of hitting the bull's eye (p), which equals 0.44, is fixed.

2. There is no set number of hits.

3. Each shot is independent of the others.

4. There are two possible outcomes: he either hits or misses the bulls' eys.

All of the binomial criteria are not met in this case.

As a result, Y cannot be stated to follow the binomial distribution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Easy-start mower Refer to Exercise 92 .

a. Calculate and interpret the mean of T.

b. Calculate and interpret the standard deviation of T.

Horse pregnanciesBigger animals tend to carry their young longer before birth. The

length of horse pregnancies from conception to birth varies according to a roughly Normal

distribution with mean 336 days and standard deviation 6 days. Let X = the length of a

randomly selected horse pregnancy.

a. Write the event “pregnancy lasts between 325 and 345 days” in terms of X. Then find

this probability.

b. Find the value of c such thatP(Xc)=0.20

Class is over! Mr. Shrager does not always let his statistics class out on time. In fact, he

seems to end class according to his own “internal clock.” The density curve here models

the distribution of Y, the amount of time after class ends (in minutes) when Mr. Shrager

dismisses the class on a randomly selected day. (A negative value indicates he ended class

early.)

a) Find and interpret P(1Y1).

b) What is μY ? Explain your answer.

c)Find the value of k that makes this statement true: localid="1654015283453" P(Yk)=0.25

Total gross profits G on a randomly selected day at Tim’s Toys follow a distribution that is approximately Normal with mean \(560 and standard deviation \)185. The cost of renting and maintaining the shop is $65 per day. Let P=profit on a randomly selected day, so P=G65. Describe the shape, center, and variability of the probability distribution of P.

Large Counts condition To use a Normal distribution to approximate binomial probabilities, why do we require that both npand n(1-p) be a t least 10?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free