Each entry in a table of random digits like Table Dhas probability $$ of being a 0 , and the digits are independent of one another. Each line of Table D contains 40 random

digits. The mean and standard deviation of the number of 0 s in a randomly selected line will be approximately

a. mean =0.1, standard deviation =0.05.

b. mean =0.1, standard deviation =0.1.

c. mean =4, standard deviation =0.05.

d. mean =4, standard deviation =1.90.

e. mean =4, standard deviation =3.60.

Short Answer

Expert verified

The correct option is (d)

Step by step solution

01

Given Information

Probability of success (p)=0.1

Number of trials(n)=4

02

Explanation for correct option

The mean and standard deviation can be calculated as:

μ=n×p=40(0.1)=4σ=n×p×(1-p)=40(0.1)(1-0.1)=1.9

The mean and standard deviation are 4 and 1.9respectively.

Hence, the correct option is (d).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Running a mile A study of 12,000able-bodied male students at the University of Illinois found that their times for the mile run were approximately Normal with mean 7.11 minutes and standard deviation 0.74 minute. 7 Choose a student at random from this group and call his time for the mile Y. Find P(Y<6). Interpret this value.

Red light! Pedro drives the same route to work on Monday through Friday. His route includes one traffic light. According to the local traffic department, there is a 55%chance

that the light will be red on a randomly selected work day. Suppose we choose 10 of Pedro's work days at random and let Y= the number of times that the light is red. Make a graph of the probability distribution of Y . Describe its shape.

Joe reads that 1 out of 4 eggs contains salmonella bacteria. So he never uses more than 3 eggs in cooking. If eggs do or don't contain salmonella independently of each other, the number of contaminated eggs when Joe uses 3 eggs chosen at random has the following distribution:

a. binomial; n=4and p=1/4

b. binomial; n=3and p=1/4

c. binomial; n=3and p=1/3

d. geometric; p=1/4

e. geometric;p=1/3

Fire insurance Suppose a homeowner spends \(300 for a home insurance policy that will pay out \)200,000 if the home is destroyed by fire in a given year. Let P = the profit made by the company on a single policy. From previous data, the probability that a home in this area will be destroyed by fire is 0.0002.

(a) Make a table that shows the probability distribution of P.

(b) Calculate the expected value of P. Explain what this result means for the insurance company.

(c) Calculate the standard deviation of P. Explain what this result means for the insurance company.

XA glass act In a process for manufacturing glassware, glass stems are sealed by heating them in a flame. Let X be the temperature (in degrees Celsius) for a randomly chosen glass. The mean and standard deviation of X are μX=550°Cand σX=5.7°C.

a. Is tempeгature a discrete ог continuous гandom variable? Explain уоuг answer.

b. The target temperature is 550°C. What are the mean and standard deviation of the number of degrees off target, D=X-550?

c. A manager asks for results in degrees Fahrenheit. The conversion of X into degrees Fahrenheit is given by Y=95X+32Y=95X+32. What are the mean μYand the standard deviation σYof the temperature of the flame in the Fahrenheit scale?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free