More homework Some skeptical Ap® Statistics students want to investigate the newspaper's claim in Exercise 11, so they choose an SRS of 100students from the school to interview. In their sample, 45students completed their homework last week. Does this provide convincing evidence that less than 60%of all students at the school completed their assigned homework last week?

a. What is the evidence that less than 60%of all students completed their assigned homework last week?

b. Provide two explanations for the evidence described in part (a).

We used technology to simulate choosing 250SRSs of size n=100n=100from a population of 2000students where 60%completed their assigned homework last week. The dotplot shows pp^the sample proportion of students who completed their assigned homework last week for each of the 250simulated samples.

c. There is one dot on the graph at 0.73. Explain what this value represents.

d. Would it be surprising to get a sample proportion of p=0.45p^=0.45or smaller in an SRS of size 100when p=0.60p=0.60? Justify your answer.

e. Based on your previous answers, is there convincing evidence that less than 60%of all students at the school completed their assigned homework last week? Explain your reasoning.

Short Answer

Expert verified

(a) The sample proportion is less than 60%i.e. 45%.

(b) It's also feasible that the sample proportion is lower than 60%because the population proportion is likewise lower than 60%.

(c) One basic random sampling of 100students revealed that 73of the 100had finished their assigned homework the previous week.

(d) Yes, it is surprising to get the sample proportion.

(e) Yes, there is a piece of convincing evidence that less than sixty percent of all students at the school completed their assigned homework last week.

Step by step solution

01

Part (a) Step 1: Given information

We need to find out the evidence for all the students completing their assigned work last week.

02

Part (a) Step 2: Explanation

We know that

The sample proportion is a division of the number of successes and sample size i.e. p^=xn=45100=0.45=45%

We should notice that the sample proportion of 45%is lower than the advertised 60%, implying that less than60% of all students at the school completed their assigned homework last week.

03

Part (b) Step 1: Given information

We need to find out the explanations for the evidence described in part (a).

04

Part (b) Step 2: Explanation

Because the population proportion is 60%and we obtained a sample with a sample proportion of only 45%by chance, the sample proportion could be less than 60%.

However, it's also feasible that the sample proportion is lower than 60%because the population proportion is likewise lower than 60%.

05

Part (c) Step 1: Given information

We need to find out the representation of value 0.73.

06

Part (c) Step 2: Explanation

Each dot in the dotplot indicates a sample proportion pfor a simple random sample (SRS) of 100students, where the sample proportion is the proportion of students in the sample who completed their assigned homework the previous week.

The dot at 0.73indicates a basic random sample of 100pupils, with 73of them having done their assigned homework the previous week (which then results in a sample proportion of 0.73).

07

Part (d) Step 1: Given information

We need to find whether it is surprising to get smaller SRS or not.

08

Part (d) Step 2: Explanation

We can see that there are no dots above 0.45and no dots to the left of 0.45in the following dotplot. As a result, obtaining a sample with a sample percentage of p=0.45is highly implausible when the population proportion is actually p=0.60, and we would be shocked if we obtained a sample with a sample proportion of p=0.45.

09

Part (e) Step 1: Given information

We need to find the convincing answer for part (d).

10

Part (e) Step 2: Explanation

We can see that there are no dots above 0.45and no dots to the left of 0.45in the following dotplot. This means that the sample proportion is very unlikely to be p=0.45when the population proportion is actually p=0.60, and we would be shocked if we got a sample with sample proportion p=0.45.

This suggests that less than 60%of all pupils at the school completed their given homework last week, according to credible information.

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Most popular questions from this chapter

Tall girls? To see if the claim made in Exercise 12is true at their high school, an Ap Statistics class chooses an SRS of twenty 16-year-old females at the school and measures their heights. In their sample, the mean height is 64.7inches. Does this provide convincing evidence that 16-year-old females at this school are taller than 64inches, on average?

a. What is the evidence that the average height of all 16-year-old females at this school is greater than 64inches, on average?

b. Provide two explanations for the evidence described in part (a).

We used technology to simulate choosing 250SRSs of size n=20from a population of three hundred 16-year-old females whose heights follow a Normal distribution with mean localid="1654113150676" μ=64inches and standard deviation μ=2.5inches. The dotplot shows x=the sample mean height for each of the 250simulated samples.

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e. Based on your previous answers, is there convincing evidence that the average height of all 16-year-old females at this school is greater than 64inches? Explain your reasoning.

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a.

b.

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