Vigorous exercise helps people live several years longer (on average). Whether mild activities like slow walking extend life is not clear. Suppose that the added life expectancy from regular slow walking is just 2 months. A significance test is more likely to find a significant increase in mean life expectancy with regular slow walking if

Step 2: Explanation

Short Answer

Expert verified

The correct option is (a).

Step by step solution

01

Given information

a. It uses a 5% significance level and is based on a very large random sample.

b. It is based on a very large random sample with a significance level of one percent.

c. It uses a 5% significance level and is based on a very small random sample.

d. It is based on a very small random sample with a significance level of one percent.

e. The number of people in the sample has no bearing on the test's significance.

02

Explanation

"It is based on a very big random sample and a significance level is applied," is the best response to the supplied statement.

There will be a difference in the mean life expectancy between individuals who perform strenuous exercise and those who do regular slow-walking since vigorous exercise leads to living several months longer on average and regular slow-walking leads to living months longer on average.

The higher the sample size, the more data regarding the difference in life expectancy will be available, and the more valid the estimates will be. However, because there is a difference in mean life expectancy, one will very certainly reject the null hypothesis, implying that a considerable increase is more plausible. So the correct option is (a).

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Most popular questions from this chapter

A researcher claims to have found a drug that causes people to grow taller. The coach of the basketball team at Brandon University has expressed interest but demands evidence. Over 1000 Brandon students volunteer to participate in an experiment to test this new drug. Fifty of the volunteers are randomly selected, their heights are measured, and they are given the drug. Two weeks later, their heights are measured again. The power of the test to detect an average increase in height of 1 inch could be increased by

a. using only volunteers from the basketball team in the experiment.

b. usingα=0.05 instead of α=0.05

c. using α=0.05instead of α=0.01

d. giving the drug to 25 randomly selected students instead of 50.

e. using a two-sided test instead of a one-sided test.

A random sample of 100 likely voters in a small city produced 59 voters in favor of Candidate A. The observed value of the standardized test statistic for performing a test of H0:p=0.5H0:p=0.5versus Ha:p>0.5Ha:p>0.5

is which of the following?

a)z=0.59-0.50.59(0.41)100

b)z=0.59-0.50.5(0.5)100

c)z=0.5-0.590.59(0.41)100

d)z=0.5-0.590.5(0.5)100

e)z=0.59-0.5100

Teens and sex The Gallup Youth Survey asked a random sample of U.S. teens aged 13 to 17 whether they thought that young people should wait until marriage to have sex.14 The Minitab output shows the results of a significance test and a 95% confidence interval based on the survey data.

a. Define the parameter of interest.

b. Check that the conditions for performing the significance test are met in this case.

c. Interpret the P-value.

d. Do these data give convincing evidence that the actual population proportion differs from 0.5? Justify your answer with appropriate evidence.

Stating hypotheses

a. A change is made that should improve student satisfaction with the parking situation at your school. Before the change, 37%of students approve of the parking that's provided. The null hypothesis H0:p=0.37H0:p^=0.37is tested against the alternative Ha: p>0.37Ha:p^>0.37

b. A researcher suspects that the mean birth weights of babies whose mothers did not see a doctor before delivery is less than 3000 grams. The researcher states the hypotheses as

H0:μ=3000gramsH0:μ=3000grams

Ha:μ2999gramsHa:μ2999grams

Pressing pills Refer to Exercise 77.

a. Construct and interpret a 95% confidence interval for the true hardness μ of the tablets in this batch. Assume that the conditions for inference are met.

b. Explain why the interval in part (a) is consistent with the result of the test in Exercise 77.

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