How much juice? Refer to Exercise 3. The mean amount of liquid in the bottles is 179.6ml and the standard deviation is 1.3ml. A significance test yields a P-value of 0.0589. Interpret the P-value.

Short Answer

Expert verified

There is a 5.89%possibility that the mean volume of liquid in a sample of 40bottles is 179.6millilitres or more extreme, when the mean volume of liquid of all bottles is180 millilitres

Step by step solution

01

Step 1:Given information

The mean amount of liquid in the bottles is 179.6mland the standard deviation is 1.3ml. A significance test yields aP-value of 0.0589

02

Step 2:Explaination

P=0.0589=5.89%

x¯=179.6

s=1.3

Claim is mean is 180

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population mean is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

H0:μ=180

Ha:μ180

The P-value is the probability of getting the value of the test static or a value more extreme, when the null hypothesis is true.

There is a 5.89%possibility that the mean volume of liquid in a sample of 40 bottles is 179.6millilitres or more extreme, when the mean volume of liquid of all bottles is180 millilitres

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Jump around Refer to Exercise 78.

a. Construct and interpret a 90% confidence interval for the true mean vertical jump μ(in inches) of the students at Haley, Jeff, and Nathan’s school. Assume that the conditions for inference are met.

b. Explain why the interval in part (a) is consistent with the result of the test in Exercise 78

Losing weight A Gallup poll found that 59% of the people in its sample said “Yes” when asked, “Would you like to lose weight?” Gallup announced: “For results based on the total sample of national adults, one can say with 95% confidence that the margin of (sampling) error is ±3 ±3percentage points.”12 Based on the confidence interval, is there convincing evidence that the true proportion of U.S. adults who would say they want to lose weight differs from 0.55? Explain your reasoning

Home computers Jason reads a report that says 80%of U.S. high school

students have a computer at home. He believes the proportion is smaller than 0.80at his large rural high school. Jason chooses an SRS of 60students and finds that 41have a computer at home. He would like to carry out a test at the α=0.05significance level of H0:p=0.80versus Ha:p<0.80, where p= the true

proportion of all students at Jason’s high school who have a computer at home. Check if the conditions for performing the significance test are met.

Home computersRefer to Exercise 35.

a. Explain why the sample result gives some evidence for the alternative hypothesis.

b. Calculate the standardized test statistic and P-value.

c. What conclusion would you make?

No homework? Refer to Exercise 1. The math teachers inspect the

homework assignments from a random sample of 50 students at the school. Only 68% of the students completed their math homework. A significance test yields a P-value of 0.1265.

a. Explain what it would mean for the null hypothesis to be true in this setting.

b. Interpret the P-value.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free