Flu vaccine Refer to ExerciseR9.5. Of the 1000 adults who were given the vaccine, 43 got the flu. Do these data provide convincing evidence to support the company’s claim?

Short Answer

Expert verified

There is not sufficient evidence to support the claim.

Step by step solution

01

Step 1:Given information

No of adults(x):1000

No of peoples got flu(n):43

02

Step 2:Calculation

So finding out the hypotheses:

H0:p=5%=0.05

Ha=p<0.05

The sample proportion is the no. of successes divided by the sample size:

p=xn=431000=0.043

Determine the value of test statistic:

z=p^-popo1-pon

z=0.043-0.050.05(1-0.05)1000

z-1.02

P- value is the probability of obtaining the value of test statistic, or a value more extreme.

For determining theP- value in tableA:

P=P(z<-1.02)=0.1539

If the P - value smaller than the significance level, reject the null hypothesis:

P>0.05, thus fails to reject theH0.

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Most popular questions from this chapter

Potato chips A company that makes potato chips requires each shipment of

potatoes to meet certain quality standards. If the company finds convincing evidence that more than 8%of the potatoes in the shipment have “blemishes,” the truck will be sent back to the supplier to get another load of potatoes. Otherwise, the entire truckload will be used to make potato chips. To make the decision, a supervisor will inspect a random sample of potatoes from the shipment. He will then perform a test of H0:p=0.08versus Ha:p>0.08, where p is the true proportion of potatoes with blemishes in a given truckload. The power of the test to detect that p=0.11, based on a random sample of 500 potatoes and significance level α=0.05, is 0.764Interpret this value.

1 A software company is trying to decide whether to produce an upgrade of one of its programs. Customers would have to pay \(100 for the upgrade. For the upgrade to be profitable, the company must sell it to more than 20% of their customers. You contact a random sample of 60 customers and find that 16 would be willing to pay \)100 for the upgrade.

a. Do the sample data give convincing evidence that more than 20% of the company’s customers are willing to purchase the upgrade? Carry out an appropriate test at the α=0.05significance level.

b. Which would be a more serious mistake in this setting—a Type I error or a Type II error? Justify your answer.

c. Suppose that 30% of the company’s customers would be willing to pay $100 for the upgrade. The power of the test to detect this fact is0.60. Interpret this value.

Tests and confidence intervals The P-value for a two-sided test of the null hypothesis H0:μ=10is0.06

a. Does the 95% confidence interval for μ include 10? Why or why not?

b. Does the 90% confidence interval for μ include 10? Why or why not?

You are testing H0:μ=10against Ha:μ<10based on an SRS of20

observations from a Normal population. The t statistic is t=2.25

The P-value

a. falls between 0.01 and 0.02.

b. falls between 0.02 and 0.04.

c. falls between 0.04 and 0.05.

d. falls between 0.05 and 0.25.

e. is greater than 0.25.

Water! A blogger claims that U.S. adults drink an average of five 8-ounce glasses (that’s 40 ounces) of water per day. Researchers wonder if this claim is true, so they ask a random sample of 24 U.S. adults about their daily water intake. A graph of the data shows a roughly symmetric shape with no outliers.

a. State an appropriate pair of hypotheses for a significance test in this setting. Be sure to define the parameter of interest.

b. Check conditions for performing the test in part (a).

c. The 90% confidence interval for the mean daily water intake is 30.35 to 36.92 ounces. Based on this interval, what conclusion would you make for a test of the hypotheses in part (a) at the 10% significance level?

d. Do we have convincing evidence that the amount of water U.S. children drink per day differs from 40 ounces? Justify your answer.

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