Chapter 15: Problem 53
A protostar with the mass of the Sun starts out with a temperature of about \(3500 \mathrm{K}\) and a luminosity about 200 times larger than the Sun's current value. Estimate this protostar's size and compare it to the size of the Sun today.
Short Answer
Expert verified
The protostar's radius is approximately 88.2 times the current radius of the Sun.
Step by step solution
01
Understand Luminosity Relation
The luminosity of a star is related to its radius and surface temperature by the formula: \[ L = 4 \pi R^2 \sigma T^4 \] where \(L\) is the luminosity, \(R\) is the radius, \(T\) is the temperature, and \(\sigma\) is the Stefan-Boltzmann constant.
02
Express the Protostar's Luminosity
Given that the protostar’s luminosity is 200 times the Sun's luminosity \(L_\odot\), we write:\[ L_{PS} = 200 L_\odot \]
03
Use the Luminosity Formula
Equate the luminosity of the protostar to the relations given and solve for the radius. Plug in the given temperature of the protostar \(3500 \mathrm{K}\) and the solar temperature \(5778 \mathrm{K}\):\[ 200 L_\odot = 4 \pi R_{PS}^2 \sigma (3500)^4 \]
04
Compare the Formula for Solar Luminosity
For the Sun, the luminosity is:\[ L_\odot = 4 \pi R_\odot^2 \sigma (5778)^4 \]
05
Solve for Protostar's Radius
Divide the protostar’s luminosity equation by the Sun's luminosity equation and solve for \(R_{PS}\):\[ \frac{200 L_\odot}{L_\odot} = \frac{R_{PS}^2 3500^4}{R_\odot^2 5778^4} \]which simplifies to: \[ 200 = \left( \frac{R_{PS}}{R_\odot} \right)^2 \left( \frac{3500}{5778} \right)^4 \]Isolate \( \frac{R_{PS}}{R_\odot} \):\[ \left( \frac{R_{PS}}{R_\odot} \right)^2 = 200 \left( \frac{5778}{3500} \right)^4 \],\[ \frac{R_{PS}}{R_\odot} = \sqrt{200} \left( \frac{5778}{3500} \right)^2 \],approximate: \[ R_{PS} \approx 88.2 R_\odot \]
06
Compare Protostar's Size to Sun
The radius of the protostar \(R_{PS}\) is approximately 88.2 times the Sun's current radius \(R_\odot\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stellar Luminosity
Stellar luminosity is a measure of the total amount of energy a star emits per unit time. This energy is radiated across all wavelengths and directions. In the study of stars, luminosity is usually compared to the Sun's luminosity, denoted as \( L_\odot \). Luminosity helps astronomers understand a star's energy output, which is crucial for determining its size and life cycle. The formula for luminosity involves several factors:
\[ L = 4 \pi R^2 \sigma T^4 \]
Here, \( R \) is the radius of the star, \( T \) is the temperature, and \( \sigma \) is the Stefan-Boltzmann constant. This equation shows that a star's luminosity depends on both its size and its surface temperature.
\[ L = 4 \pi R^2 \sigma T^4 \]
Here, \( R \) is the radius of the star, \( T \) is the temperature, and \( \sigma \) is the Stefan-Boltzmann constant. This equation shows that a star's luminosity depends on both its size and its surface temperature.
Radius-Temperature Relation
The radius-temperature relation indicates how a star's size changes with temperature. For a given luminosity, a hotter star must have a smaller radius than a cooler star. This relationship is vital for estimating the size of stars, including protostars, which are in the early stages of stellar development. If we know a star's luminosity and temperature, we can rearrange the luminosity formula to solve for the radius:
\[ R = \sqrt{ \frac{L}{4 \pi \sigma T^4} } \]
This relation is helpful for comparing different types of stars. It also allows us to understand how a star's structure changes as it evolves.
\[ R = \sqrt{ \frac{L}{4 \pi \sigma T^4} } \]
This relation is helpful for comparing different types of stars. It also allows us to understand how a star's structure changes as it evolves.
Stefan-Boltzmann Law
The Stefan-Boltzmann law connects the power emitted per unit area of a black body to its absolute temperature. It is expressed as:
\[ E = \sigma T^4 \]
Here, \( E \) is the energy emitted per unit area, \( T \) is the absolute temperature, and \( \sigma \) is the Stefan-Boltzmann constant \( ( \sigma = 5.67 \times 10^{-8} \ \text{W} \ \text{m}^{-2} \ \text{K}^{-4} \ ) \). This law is fundamental in astrophysics and helps describe how energy radiates from stars. By applying this law, we can understand the relationship between a star's temperature and its emitted energy, which in turn helps us determine its luminosity and size.
\[ E = \sigma T^4 \]
Here, \( E \) is the energy emitted per unit area, \( T \) is the absolute temperature, and \( \sigma \) is the Stefan-Boltzmann constant \( ( \sigma = 5.67 \times 10^{-8} \ \text{W} \ \text{m}^{-2} \ \text{K}^{-4} \ ) \). This law is fundamental in astrophysics and helps describe how energy radiates from stars. By applying this law, we can understand the relationship between a star's temperature and its emitted energy, which in turn helps us determine its luminosity and size.
Solar Comparison
Comparing other stars to our Sun provides important benchmarks, as the Sun serves as a standard reference. When estimating the size of a protostar, we often compare its properties to those of the Sun. In the provided problem, the protostar’s luminosity is 200 times that of the Sun. Given that the Sun’s temperature is \( 5778 \ \text{K} \) and its luminosity is \( L_\odot \), the size of the protostar can be calculated using the radius-temperature relation and Stefan-Boltzmann law.
After using these principles, we find that the protostar is approximately 88.2 times the Sun's current radius. Such comparisons help students understand the scale and diversity of stellar objects in the universe.
After using these principles, we find that the protostar is approximately 88.2 times the Sun's current radius. Such comparisons help students understand the scale and diversity of stellar objects in the universe.