Chapter 20: Problem 50
A quasar has a luminosity of \(10^{41}\) watts \((\mathrm{W}),\) or \(\mathrm{J} / \mathrm{s}\), and \(10^{8} M_{\circ}\) to feed it. Assuming constant luminosity and 20 percent conversion efficiency, what is your estimate of the quasar's lifetime?
Short Answer
Expert verified
The quasar's lifetime is approximately 113.4 million years.
Step by step solution
01
Understand Key Terms
Identify the given values: luminosity of the quasar, mass available for energy conversion, and the conversion efficiency. The quasar's luminosity is given as \(10^{41}\) watts, the mass available is \(10^{8} M_{\bullet}\), and the conversion efficiency is 20%.
02
Calculate Energy from Mass
Use Einstein's mass-energy equivalence formula, \(E = mc^2\), to find the total energy from the mass. Here \(m = 10^{8} M_{\bullet}\) where \(1 M_{\bullet} = 1.989 \times 10^{30}\) kg.
03
Convert Mass to Energy
Calculate the energy by substituting the known values: \[ E = (10^{8} \times 1.989 \times 10^{30} \text{ kg}) \times (3 \times 10^8 \text{ m/s})^2 \ E = 1.789 \times 10^{54} \text{ joules} \ \text{Since conversion efficiency is 20%, only 20% of this energy is used:} \ E_{\text{usable}} = 0.2 \times 1.789 \times 10^{54} \text{ J} = 3.578 \times 10^{53} \text{ J} \]
04
Calculate Lifetime
The lifetime of the quasar can be calculated by dividing the total usable energy by its luminosity: \[ t = \frac{E_{\text{usable}}}{L} \ t = \frac{3.578 \times 10^{53} \text{ J}}{10^{41} \text{ W}} = 3.578 \times 10^{12} \text{ seconds} \]
05
Convert to Years
Since there are approximately 31,536,000 seconds in a year, convert the time to years: \[ t_{\text{years}} = \frac{3.578 \times 10^{12} \text{ s}}{31,536,000 \text{ s/year}} \ t_{\text{years}} \ \text{ Rounding to significant figures, } t_{\text{years}} \text{ approximately } 113.4 \text{ million years which is } 113.4 \times 10^6 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass-Energy Equivalence
The concept of mass-energy equivalence is one of Einstein's most famous theories, given by the equation \[ E = mc^2 \] where \( E \) is energy, \( m \) is mass, and \( c \) is the speed of light in a vacuum, approximately \( 3 \times 10^8 \) m/s.
This equation tells us that mass can be converted into a huge amount of energy.
In the context of our quasar, we can use this equation to convert the quasar's mass into energy.
The available mass is \( 10^8 M_\odot \) and each solar mass \( M_\odot \) is about \( 1.989 \times 10^{30} \) kg.
This tells us how much energy is available to power the quasar's luminosity.
The energy from mass is calculated as: \[ E = (10^8 \times 1.989 \times 10^{30} \text{ kg}) \times (3 \times 10^8 \text{ m/s})^2 = 1.789 \times 10^{54} \text { joules} \]
This equation tells us that mass can be converted into a huge amount of energy.
In the context of our quasar, we can use this equation to convert the quasar's mass into energy.
The available mass is \( 10^8 M_\odot \) and each solar mass \( M_\odot \) is about \( 1.989 \times 10^{30} \) kg.
This tells us how much energy is available to power the quasar's luminosity.
The energy from mass is calculated as: \[ E = (10^8 \times 1.989 \times 10^{30} \text{ kg}) \times (3 \times 10^8 \text{ m/s})^2 = 1.789 \times 10^{54} \text { joules} \]
Luminosity
Luminosity is a measure of how much energy a celestial object like a quasar emits per second.
It's expressed in watts (W), which is equivalent to joules per second \((\text{J/s})\).
In simpler terms, it's the brightness of the object.
Our quasar has a luminosity of \( 10^{41} \) watts. This indicates how quickly the quasar is emitting energy. The challenge is to sustain this rate of energy emission over time.
To find the quasar's lifetime, we will divide the total available energy by this luminosity.
This will tell us how long the energy can support the quasar's brightness.
It's expressed in watts (W), which is equivalent to joules per second \((\text{J/s})\).
In simpler terms, it's the brightness of the object.
Our quasar has a luminosity of \( 10^{41} \) watts. This indicates how quickly the quasar is emitting energy. The challenge is to sustain this rate of energy emission over time.
To find the quasar's lifetime, we will divide the total available energy by this luminosity.
This will tell us how long the energy can support the quasar's brightness.
Energy Conversion Efficiency
Not all the mass-energy of the quasar is actually converted into useful energy.
This is because energy conversion processes are not 100% efficient.
In our example, only 20% of the total mass-energy is converted into usable energy.
This efficiency is given as a percentage and indicates how much of the initial input gets turned into useful output. According to the given conversion efficiency of 20%, we calculate: \[ E_{\text{usable}} = 0.2 \times 1.789 \times 10^{54} \text{ J} = 3.578 \times 10^{53} \text{ J} \] Only this fraction of energy will be used to power the quasar.
This is because energy conversion processes are not 100% efficient.
In our example, only 20% of the total mass-energy is converted into usable energy.
This efficiency is given as a percentage and indicates how much of the initial input gets turned into useful output. According to the given conversion efficiency of 20%, we calculate: \[ E_{\text{usable}} = 0.2 \times 1.789 \times 10^{54} \text{ J} = 3.578 \times 10^{53} \text{ J} \] Only this fraction of energy will be used to power the quasar.
Time Conversion
How long will the quasar shine?
We need to find its lifetime.
This is done by taking the total usable energy and dividing it by the luminosity: \[ t = \frac{3.578 \times 10^{53} \text{ J}}{10^{41} \text{ W}} = 3.578 \times 10^{12} \text{ seconds} \]
But we generally prefer a more relatable unit like years. There are approximately 31,536,000 seconds in a year, so we convert the quasar's lifetime to years: \[ t_{\text{years}} = \frac{3.578 \times 10^{12} \text{ s}}{31,536,000 \text{ s/year}} = 113.4 \times 10^{6} \] Therefore, the quasar will shine for roughly 113.4 million years.
We need to find its lifetime.
This is done by taking the total usable energy and dividing it by the luminosity: \[ t = \frac{3.578 \times 10^{53} \text{ J}}{10^{41} \text{ W}} = 3.578 \times 10^{12} \text{ seconds} \]
But we generally prefer a more relatable unit like years. There are approximately 31,536,000 seconds in a year, so we convert the quasar's lifetime to years: \[ t_{\text{years}} = \frac{3.578 \times 10^{12} \text{ s}}{31,536,000 \text{ s/year}} = 113.4 \times 10^{6} \] Therefore, the quasar will shine for roughly 113.4 million years.