Chapter 6: Problem 46
Assume that the maximum aperture of the human eye, \(D\), is approximately \(8 \mathrm{mm}\) and the average wavelength of visible light, \(\lambda,\) is \(5.5 \times 10^{-4} \mathrm{mm}\) a. Calculate the diffraction limit of the human eye in visible light. b. How does the diffraction limit compare with the actual resolution of \(1-2\) arcmin \((60-120 \text { arcsec }) ?\) c. To what do you attribute the difference?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.