Each form of energy generation in stars depends on temperature. a. The rate of hydrogen fusion (proton-proton chain) near \(10^{7} \mathrm{K}\) increases with temperature as \(T^{4} .\) If the temperature of the hydrogen- burning core is raised by 10 percent, how much does the hydrogen fusion energy increase? b. Helium fusion (the triple-alpha process) at \(10^{8} \mathrm{K}\) increases with an increase in temperature at a rate of \(T^{40}\). If the temperature of the helium-burning core is raised by 10 percent, how much does the helium fusion energy increase?

Short Answer

Expert verified
a. Hydrogen fusion energy increases by 46.41%. b. Helium fusion energy increases by 4,425.9%.

Step by step solution

01

Understand the formula for rate of hydrogen fusion

Given that the rate of hydrogen fusion depends on temperature as per the equation: \[ \text{Rate of hydrogen fusion} \times T^4 \] where T is the temperature.
02

Calculate the factor increase in temperature for hydrogen fusion

The temperature is raised by 10%, so the new temperature, T', is: \[ T' = 1.1T \]
03

Calculate the new rate of hydrogen fusion

Substitute the new temperature into the power equation: \[ \text{Rate of hydrogen fusion} \times (1.1T)^4 \] Simplifying this: \[ (1.1)^4 \times T^4 \] The calculation of \( (1.1)^4 \) gives approximately 1.4641.
04

Interpret the result for hydrogen fusion

The hydrogen fusion energy increases by a factor of approximately 1.4641, or 46.41%.
05

Understand the formula for rate of helium fusion

Given that the rate of helium fusion increases with temperature as per the equation: \[ \text{Rate of helium fusion} \times T^{40} \] where T is the temperature.
06

Calculate the factor increase in temperature for helium fusion

The temperature is raised by 10%, so the new temperature, T', is: \[ T' = 1.1T \]
07

Calculate the new rate of helium fusion

Substitute the new temperature into the power equation: \[ \text{Rate of helium fusion} \times (1.1T)^{40} \] Simplifying this: \[ (1.1)^{40} \times T^{40} \] The calculation of \( (1.1)^{40} \) gives approximately 45.259.
08

Interpret the result for helium fusion

The helium fusion energy increases by a factor of approximately 45.259, or 4,425.9%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Fusion
Hydrogen fusion is the primary process by which stars generate energy. It occurs through the proton-proton chain reaction, primarily happening in the cores of stars like our Sun, at around \(10^7 \) K. In this reaction, four hydrogen nuclei (protons) are fused to form a single helium nucleus, releasing a significant amount of energy in the form of radiation and subatomic particles. The rate of this fusion reaction is highly temperature dependent, following T^4, which denotes that even small increases in temperature can hugely elevate the fusion rate. For instance, if the temperature is increased by 10%, the fusion rate boosts by a factor of (1.1)^4, which is approximately 1.4641. This translates to a 46.41% increase in energy output, showcasing the sensitive nature of fusion reactions to temperature changes.
Helium Fusion
Once a star has exhausted its hydrogen fuel, it begins to burn helium in a process called the triple-alpha reaction. This process occurs at much higher temperatures, around \(10^8 \) K. In helium fusion, three helium nuclei combine to form carbon, releasing energy in the process. The rate of helium fusion follows a T^{40} dependence, which is extremely sensitive to temperature changes. To illustrate, if the temperature of a helium-burning core is increased by just 10%, the rate of helium fusion energy increases dramatically. Specifically, the reaction rate increases by a factor of (1.1)^{40}, which is approximately 45.259. Therefore, the fusion energy output soars by 4,425.9%, indicating how a small temperature increase can lead to a massive surge in energy production during helium burning.
Temperature Dependence
Understanding the temperature dependence of fusion reactions is crucial in astrophysics. Both hydrogen and helium fusion rates are exponents of temperature but with different growth rates. The proton-proton chain (hydrogen fusion) follows a T^4 dependence, meaning that a 10% increase in temperature causes a roughly 46.41% rise in energy output. On the other hand, the triple-alpha process (helium fusion) with its T^{40} dependence shows that a similar 10% temperature rise can cause a staggering 4,425.9% increase in energy output.
This significant temperature dependence explains why stars undergo different stages of burning: starting with hydrogen fusion at lower temperatures and shifting to helium fusion at higher core temperatures as they evolve. It also emphasizes the delicate balance maintained in stellar cores to prevent runaway reactions, which could lead to explosive scenarios known as novae or supernovae.

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Most popular questions from this chapter

Place the main-sequence lifetimes of the following stars in order from shortest to longest. a. the Sun: mass \(1 M_{\text {sun }}\), luminosity \(1 L_{\text {sun }}\) b. Capella Aa: mass 3 \(M_{\text {sun }}\), luminosity 76 \(L_{\text {Sun }}\) c. Rigel: mass \(24 M_{\text {sun }}\), luminosity \(85,000 L_{\text {sun }}\) d. Sirius A: mass 2 \(M_{\text {sun }}\), luminosity 25 \(L_{\text {sun }}\) e. Canopus: mass \(8.5 M_{\text {sun }}\), luminosity \(13,600 L_{\text {sun }}\) f. Achernar: mass \(7 M_{\text {sun }}\), luminosity \(3,150 L_{\text {sun }}\)

When the Sun runs out of hydrogen in its core, it will become larger and more luminous because a. it will start fusing hydrogen in a shell around a helium core. b. it will start fusing helium in a shell and hydrogen in the core c. infalling material will rebound off the core and puffs up the star. d. energy balance will no longer hold, and the star will drift apart.

A white dwarf is located in the lower left of the H-R diagram. From this information alone, you can determine that a. it is very massive. b. it is very dense. c. it is very hot. d. it is very bright.

Post-main-sequence stars lose up to 50 percent of their mass because a. jets from the poles release material at an increasing rate. b. the mass of the star drops because of mass loss from fusion. c. the magnetic field causes increasing numbers of coronal mass ejections. d. the star swells until the surface gravity is too weak to hold material

Suppose a main-sequence star suddenly started burning hydrogen at a faster rate in its core. How would the star react? Discuss changes in size, temperature, and luminosity.

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