Chapter 2: Problem 8
A fair six-sided die is thrown \(N\) times and the result of each throw is recorded. (a) If the die is thrown \(N=12\) times, what is the probability that odd numbers occur three times? If it is thrown \(N=120\) times, what is the probability that odd numbers occur 30 times? Use the binomial distribution. (b) Compute the same quantities as in part (a) but use the Gaussian distribution. (Note: For part (a) compute your answers to four places.) (c) Plot the binomial and Gaussian distributions for \(N=2\) and \(N=12\).
Short Answer
Step by step solution
Define Binomial Distribution
Determine Parameters for Binomial Distribution
Compute Binomial Probability for N=12
Compute Binomial Probability for N=120
Define Gaussian Distribution
Compute Gaussian Approximation for N=12
Compute Gaussian Approximation for N=120
Plot Distributions for N=2 and N=12
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Distribution
To calculate the probability that a specific number of successes occurs, we use the formula: \[ P(X = k) = \binom{N}{k} p^k (1-p)^{N-k} \] Here's a breakdown of the components:
- **N**: Number of trials
- **k**: Number of successes
- **p**: Probability of success on each trial
- **\(\binom{N}{k}\)**: Binomial coefficient, which counts the number of ways to choose k successes from N trials
- **N** = 12
- **k** = 3
- **p** = 0.5 (since half the sides of a die are odd numbers)
Gaussian Distribution
The Gaussian distribution formula is: \[ P(X = k) \approx \frac{1}{\sqrt{2\pi \sigma^2}} e^{-\frac{(k - \mu)^2}{2\sigma^2}} \] Here:
- **\(\mu\)**: Mean of the distribution, given by \(Np\)
- **\(\sigma^2\)**: Variance of the distribution, given by \(Np(1-p)\)
- For **N = 12** and **k = 3**, with \( \mu = 12 \times 0.5 = 6\) and \( \sigma^2 = 12 \times 0.5 \times 0.5 = 3\), we use the Gaussian formula to get: \( P(X = 3) \approx 0.0807\)
- For **N = 120** and **k = 30**, with \( \mu = 60\) and \( \sigma^2 = 30\), the Gaussian formula gives us: \( P(X = 30) \approx 1.47 \times 10^{-7} \)
Probability Calculation
In the context of binomial and Gaussian distributions, probability calculations help in determining the likelihood of a certain number of successes (k) in a fixed number of trials (N).
Let's revisit the die example for a clear illustration:
- For **binomial distribution**, the calculation for getting 3 odd numbers out of 12 rolls when the probability of an odd number (success) is 0.5 is: \( P(X = 3) \approx 0.0537 \). This tells us there is about a 5.37% chance this event will occur.
- Using the **Gaussian approximation** for the same, we have: \( P(X = 3) \approx 0.0807 \) for 12 trials, showing a slightly different probability when approximated.
Statistical Approximation
The reason behind using approximations is to make calculations more manageable, especially as values of N increase. Approximations are practical because:
- **Computational Simplicity**: Calculating factorials in the binomial coefficient (\( \binom{N}{k} \)) for large N can be cumbersome. Gaussian approximation is computationally less intensive.
- **Predictive Accuracy**: The Gaussian distribution often provides a close estimation of the binomial probabilities when N is large and p is not too close to 0 or 1.
- For **N = 120** and **k = 30**, exact binomial probability: \( P(X = 30) \approx 0.0108 \)
- Gaussian approximation gives a very low probability: \( P(X = 30) \approx 1.47 \times 10^{-7} \)
Plotting Distributions
Creating plots for binomial and Gaussian distributions helps to understand their similarities and differences better.
For example, let's consider the following cases:
- **N = 2**: - **Binomial Distribution**: Plot the probability for 0, 1, and 2 successes. - **Gaussian Distribution**: Not very relevant here as N is too small for an accurate approximation.
- **N = 12**: - **Binomial Distribution**: Plot the probability for getting different numbers of successes out of 12 trials. - **Gaussian Distribution**: Superimpose a normal curve using the same mean (\( \mu = Np \)) and variance (\( \sigma^2 = Np(1-p) \)).