Show that \(T \mathrm{~d} s=c_{x}(\partial T / \partial Y)_{x} \mathrm{~d} Y+c_{Y}(\partial T / \partial x)_{Y} \mathrm{~d} x\), where \(x=X / n\) is the amount of extensive variable, \(X\), per mole, \(c_{x}\) is the heat capacity per mole at constant \(x\), and \(c_{Y}\) is the heat capacity per mole at constant \(Y\).

Short Answer

Expert verified
Use the definitions of heat capacities, express ds as a differential, multiply by T, and combine the terms.

Step by step solution

01

- Understand the Given Equation

The equation that needs to be shown is: \[ T \, d s = c_{x} \left( \frac{\partial T}{\partial Y} \right)_{x} \, dY + c_{Y} \left( \frac{\partial T}{\partial x} \right)_{Y} \, dx \]Where:- x = \( \frac{X}{n} \): Extensive variable per mole- \( c_x \): Heat capacity per mole at constant x- \( c_Y \): Heat capacity per mole at constant Y
02

- Recall Basic Thermodynamic Relationships

The specific heat capacities are defined by the following relationships:\[ c_{x} = T \left( \frac{\partial s}{\partial T} \right)_{x} \]\[ c_{Y} = T \left( \frac{\partial s}{\partial T} \right)_{Y} \]
03

- Express Differential Entropy Change

Consider the total differential change in entropy, s:\[ d s = \left( \frac{\partial s}{\partial T} \right)_{x} \, d T + \left( \frac{\partial s}{\partial x} \right)_{T} \, d x \]Similarly, for another variable Y, we can write:\[ d s = \left( \frac{\partial s}{\partial T} \right)_{Y} \, d T + \left( \frac{\partial s}{\partial Y} \right)_{T} \, d Y \]
04

- Substitute Heat Capacities into Differential Entropy Expression

Utilize the heat capacities definitions:\[ \left( \frac{\partial s}{\partial T} \right)_{x} = \frac{c_x}{T}, \quad \left( \frac{\partial s}{\partial T} \right)_{Y} = \frac{c_Y}{T} \]This gives:\[ d s = \frac{c_x}{T} \, d T + \left( T \frac{\partial s}{\partial x} \right) d x \]\[ d s = \frac{c_Y}{T} \, d T + \left( T \frac{\partial s}{\partial Y} \right) d Y \]
05

- Multiply Entire Differential Equations by Temperature

Multiply both differential equations by T:\[ T \, d s = c_x \, d T + T \left( \frac{\partial s}{\partial x} \right) \, d x \]\[ T \, d s = c_Y \, d T + T \left( \frac{\partial s}{\partial Y} \right) \, d Y \]
06

- Combine Terms to Show the Required Equation

Combine the individual equations under similar grouping factors to express as (dx and dY separated components):\[ T \, d s = c_x \left( \frac{\partial T}{\partial Y} \right)_{x} \, d Y + c_Y \left( \frac{\partial T}{\partial x} \right)_{Y} \, d x \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

heat capacity
Heat capacity is a measure of the amount of heat energy required to change the temperature of a substance by a certain amount. Specifically, it is the heat energy needed to raise the temperature of one mole of a substance by one degree Celsius or Kelvin. Heat capacity can vary depending on whether the measurement is made at constant volume (denoted as \(c_v\)) or constant pressure (denoted as \(c_p\)). In the context of the given exercise, heat capacity per mole at constants x and Y are denoted as \(c_x\) and \(c_Y\) respectively, where x and Y are specific variables related to the problem.
  • \(c_x\): Heat capacity at constant x
  • \(c_Y\): Heat capacity at constant Y
Heat capacity is crucial in understanding how much energy is needed to attain a specific temperature change. This concept is integral to the equation provided in the problem, as it helps to express differential relationships involving temperature and entropy changes. In thermodynamic systems, these capacities help in defining how systems store energy and how they respond to energy inputs.
entropy
Entropy is a fundamental concept in thermodynamics representing the degree of disorder or randomness in a system. It quantifies the number of microscopic configurations that correspond to a thermodynamic system's macroscopic state. An increase in entropy generally indicates an increase in disorder and energy dispersal within a system.
  • Defined as a state function: entropy depends only on the state's initial and final conditions, not on the process taken to get from one to the other.
  • Units: Entropy is typically measured in Joules per Kelvin (J/K).
In the given exercise, the differential change in entropy, denoted as \(ds\), plays a key role. The relationship between heat capacities and entropy is expressed through partial derivatives and the differentials of temperature and specific variables x and Y. This relationship is essential to thermodynamic processes, such as determining the efficiency and feasibility of thermodynamic cycles.
differential equations
Differential equations in thermodynamics describe how variables change with respect to each other. These equations are vital tools for modeling and predicting behavior in physical systems.
  • Differential equations provide relationships between state variables (such as temperature, pressure, entropy) and changes within a system.
  • In the problem, differential equations are used to express changes in entropy (\(ds\)) and temperature (\(dT\)) in terms of other variables.
The specific differential expression derived in the exercise links heat capacities with the partial derivatives of temperature concerning specific variables x and Y. This mathematical formulation allows us to see how small changes in state variables impact the overall state of the system, providing insights into the system's thermodynamic behavior.
thermodynamic relationships
Thermodynamic relationships form the backbone of how we understand physical systems' behavior under different conditions. These relationships are often expressed through equations and laws that connect various thermodynamic properties, such as pressure, volume, temperature, entropy, and energy.
  • State functions: Properties like entropy, enthalpy, and internal energy depend only on the system's state, not on how it reached that state.
  • Partial derivatives: These derivatives help articulate how a change in one variable influences another while keeping a third variable constant.
In the context of our exercise, the relationship involves connecting heat capacities at constant conditions (x and Y) with entropy and temperature changes. By manipulating and combining differential equations, we can derive more meaningful expressions that describe the interconnected behavior of thermodynamic properties. Understanding these relationships allows us to predict how energy transfers and transformations occur within a system.

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Most popular questions from this chapter

A boy blows a soap bubble of radius \(R\) which floats in the air a few moments before breaking. What is the difference in pressure between the air inside the bubble and the air outside the bubble when (a) \(R=1 \mathrm{~cm}\) and (b) \(R=1 \mathrm{~mm}\) ? The surface tension of the soap solution is \(\sigma=25\) \(\mathrm{dyn} / \mathrm{cm}\). (Note that soap bubbles have two surfaces.)

A solution of particles A and B has a Gibbs free energy $$ \begin{aligned} G\left(P, T, \mathrm{n}_{\mathrm{A}}, \mathrm{n}_{\mathrm{B}}\right)=& \mathrm{n}_{\mathrm{A}} g_{\mathrm{A}}(P, T)+\mathrm{n}_{\mathrm{B}} g_{\mathrm{B}}(P, T)+\frac{1}{2} \lambda_{\mathrm{AA}} \frac{\mathrm{n}_{\mathrm{A}}^{2}}{\mathrm{n}}+\frac{1}{2} \lambda_{\mathrm{BB}} \frac{\mathrm{n}_{\mathrm{B}}^{2}}{\mathrm{n}} \\ &+\lambda_{\mathrm{AB}} \frac{\mathrm{n}_{\mathrm{A}} \mathrm{n}_{\mathrm{B}}}{\mathrm{n}}+\mathrm{n}_{\mathrm{A}} R T \ln x_{\mathrm{A}}+\mathrm{n}_{\mathrm{B}} R T \ln x_{\mathrm{B}} \end{aligned} $$ Initially, the solution has \(\mathrm{n}_{\mathrm{A}}\) moles of A and \(\mathrm{n}_{\mathrm{B}}\) moles of B. (a) If an amount \(\Delta \mathrm{n}_{\mathrm{B} \text {, of } \mathrm{B} \text { is added }}\) keeping the pressure and temperature fixed, what is the change in the chemical potential of A? (b) For the case \(\lambda_{\mathrm{AA}}=\lambda_{\mathrm{BB}}=\lambda_{\mathrm{AB} \text {, }}\) does the chemical potential of A increase or decrease?

Electromagnetic radiation in an evacuated vessel of volume \(V\) at equilibrium with the walls at temperature \(T\) (blackbody radiation) behaves like a gas of photons having internal energy \(U=a V T^{4}\) and pressure \(P=1 / 3 a T^{4}\), where \(a\) is Stefan's constant. (a) Plot the closed curve in the \(P-V\) plane for a Carnot cycle using blackbody radiation. (b) Derive explicitly the efficiency of a Carnot engine which uses blackbody radiation as its working substance.

A stochastic process, involving three fluctuating quantities, \(x_{1}, x_{2}\), and \(x_{3}\), has a probability distribution $$ P\left(x_{1}, x_{2}, x_{3}\right)=C \exp \left[-\frac{1}{2}\left(2 x_{1}^{2}+2 x_{1} x_{2}+4 x_{2}^{2}+2 x_{1} x_{3}+2 x_{2} x_{3}+2 x_{3}^{2}\right)\right] $$ where \(C\) is the normalization constant. (a) Write probability distribution in the form \(P\left(x_{1}, x_{2}, x_{3}\right)=C \exp \left(-1 / 2 x^{T} \cdot g+x\right)\), where \(g\) is a \(3 \times 3\) symmetric matrix, \(x\) is a column matrix with matrix elements \(x_{i}, i=1,2,3\), and \(x^{T}\) is its transpose. Obtain the matrix \(\boldsymbol{g}\) and its inverse \(g^{-1}\). (b) Find the eigenvalues \(\lambda_{i}(i=1,2,3)\) and orthonormal eigenvectors of \(\boldsymbol{g}\) and obtain the \(3 \times 3\) orthogonal matrix \(\boldsymbol{O}\) that diagonalizes the matrix \(\boldsymbol{g}\) (get numbers for all of them). Using this orthogonal matrix, we can write \(x^{\mathrm{T}} \cdot g \cdot x=x^{\mathrm{T}} \cdot \boldsymbol{O}^{\mathrm{T}} \cdot \boldsymbol{O} \cdot g \cdot \boldsymbol{O}^{\mathrm{T}} \cdot \boldsymbol{O} \cdot \boldsymbol{x}=\boldsymbol{a}^{\mathrm{T}} \cdot \bar{\Lambda} \cdot \boldsymbol{a}=\sum_{i=1}^{3} \lambda_{i} a_{i}^{2}\) where \(\boldsymbol{O} \cdot g \cdot \boldsymbol{O}^{\mathrm{T}}=\bar{\Lambda}\) is a \(3 \mathrm{x}\) 3 diagonal matrix with matrix elements \((\bar{A})_{i, j}=\lambda_{i} \delta_{i, j}\) and \(\boldsymbol{O} \cdot \boldsymbol{x}=\boldsymbol{a}\) is a column matrix with elements, \(a_{i}(i=1,2,3)\). (c) Compute the normalization constant, C. (d) Compute the moments \(\left(x_{i}\right)(i=1,2,3),\left\langle x_{i} x_{j}\right\rangle(i=1,2,3, j=1,2,3)\left(x_{1}^{2} x_{2} x_{3}\right)\) and \(\left\langle x_{1} x_{2}^{2} x_{3}\right\rangle+\) (Note that Exercises \(\mathrm{A.7}\) and \(\mathrm{A} .8\) might be helpful.)

A heat engine uses blackbody radiation as its operating substance. The equation of state for blackbody radiation is \(P=1 / 3 a T^{4}\) and the internal energy is \(U=a V T^{4}\), where \(a=7.566 \times 10^{-16}\) \(\mathrm{J} /\left(\mathrm{m}^{3} \mathrm{~K}^{4}\right)\) is Stefan's constant, \(P\) is pressure, \(T\) is temperature, and \(V\) is volume. The engine cycle consists of three steps. Process \(1 \rightarrow 2\) is an expansion at constant pressure \(P_{1}=P_{2} .\) Process \(2 \rightarrow 3\) is a decrease in pressure from \(P_{2}\) to \(P_{3}\) at constant volume \(V_{2}=V_{3}\). Process \(3 \rightarrow 1\) is an adiabatic contraction from volume \(V_{3}\) to \(V_{1}\). Assume that \(P_{1}=3.375 P_{3}, T_{1}=2000 \mathrm{~K}\), and \(V_{1}=10^{-3} \mathrm{~m}^{3}\). (a) Express \(V_{2}\) in terms of \(V_{1}\) and \(T_{1}=T_{2}\) in terms of \(T_{3}\) (b) Compute the work done during each part of the cycle. (c) Compute the heat absorbed during each part of the cycle. (d) What is the efficiency of this heat engine (get a number)? (e) What is the efficiency of a Carnot engine operating between the highest and lowest temperatures.

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