Chapter 4: Problem 5
Consider the vaporization curve for liquid mercury. The latent heat of vaporization, \(L\) (in \(\mathrm{J} / \mathrm{mol}\) ) varies slowly with pressure, but has significant variation with temperature and can be written \(L=(7724-0.9768 T) R\), where \(R\) is the gas constant and \(T\) is measured in kelvin. It is known that at atmospheric pressure ( \(P_{\mathrm{am}}=1.013 \times 10^{5} \mathrm{~Pa}\) ) mercury begins to vaporize at temperature \(T=\) \(630 \mathrm{~K}\). (a) Plot the vaporization curve for mercury between temperatures \(T=500 \mathrm{~K}\) and \(T=650 \mathrm{~K}\). (b) At what pressure does mercury begin to vaporize when \(T=530 \mathrm{~K}\) ? (Hint: The volume of the liquid mercury can be neglected relative to that of the vapor and the vapor can be treated as an ideal gas.)
Short Answer
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Key Concepts
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