Prove that the probability of finding an atom in any particular energy level is P(E)=(1/Z)e-F/kT, whereF=E-TS and the "'entropy" of a level is k times the logarithm of the number of degenerate states for that level.

Short Answer

Expert verified

Hence proved that the probability of finding an atom in any particular energy level is:P(E)=(1/Z)e-F/kT

Step by step solution

01

Given information

The probability of finding an atom in any particular energy level is

P(E)=(1/Z)e-F/kTwhere F=E-TS

02

Explanation

Assume we have an n-degenerate level; the chance of a system being in that level is just n multiplied by the probability of being in any of the states, as follows:

P(E)=nP(s)

From equation 6.8, for any state we have:

P(s)=1Ze-E(s)/kT

Substitute into the above equation

P(E)=1Zne-E(s)/kT(1)

The entropy of the system will be:

S=kln(n)ln(n)=Skn=eS/k

03

Calculations

Substitute the value of n in equation (1)

P(E)=1ZeS/ke-E(s)/kTP(E)=1ZeS/k-E(s)/kTP(E)=1ZeTS/kT-E(s)/kTP(E)=1Ze(TS-E(s))/kT

Using F=E(s)-TSwhere F is the Helmholtz free energy:

P(E)=1Ze-F/kT

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Most popular questions from this chapter

In the real world, most oscillators are not perfectly harmonic. For a quantum oscillator, this means that the spacing between energy levels is not exactly uniform. The vibrational levels of an H2 molecule, for example, are more accurately described by the approximate formula

Enϵ1.03n-0.03n2,n=0,1,2,

where ϵ is the spacing between the two lowest levels. Thus, the levels get closer together with increasing energy. (This formula is reasonably accurate only up to about n = 15; for slightly higher n it would say that En decreases with increasing n. In fact, the molecule dissociates and there are no more discrete levels beyond n 15.) Use a computer to calculate the partition function, average energy, and heat capacity of a system with this set of energy levels. Include all levels through n = 15, but check to see how the results change when you include fewer levels Plot the heat capacity as a function of kT/ϵ. Compare to the case of a perfectly harmonic oscillator with evenly spaced levels, and also to the vibrational portion of the graph in Figure 1.13.

For a CO molecule, the constant ϵis approximately 0.00024eV. (This number is measured using microwave spectroscopy, that is, by measuring the microwave frequencies needed to excite the molecules into higher rotational states.) Calculate the rotational partition function for a COmolecule at room temperature (300K), first using the exact formula 6.30 and then using the approximate formula 6.31.

Some advances textbooks define entropy by the formula

S=-ksPslnPs

where the sum runs over all microstates accessible to the system and Psis the probability of the system being in microstate s.

(a) For an isolated system, role="math" localid="1647056883940" Ps=1Ωfor all accessible states s. Show that in this case the preceding formula reduces to our familiar definition of entropy.

(b) For a system in thermal equilibrium with a reservoir at temperatureT,role="math" localid="1647057328146" Ps=e-EskTZ. Show that in this case as well, the preceding formula agrees with what we already know about entropy.

A particle near earth's surface traveling faster than about 11km/shas enough kinetic energy to completely escape from the earth, despite earth's gravitational pull. Molecules in the upper atmosphere that are moving faster than this will therefore escape if they do not suffer any collisions on the way out.

(a) The temperature of earth's upper atmosphere is actually quite high, around 1000K.Calculate the probability of a nitrogen molecule at this temperature moving faster than 11km/s, and comment on the result.

(b) Repeat the calculation for a hydrogen molecule (H2)and for a helium atom, and discuss the implications.

(c) Escape speed from the moon's surface is only about 2.4km/s. Explain why the moon has no atmosphere.

For a COmolecule, the constant is approximately 0.00024eV.(This number is measured using microwave spectroscopy, that is, by measuring the microwave frequencies needed to excite the molecules into higher rotational states.) Calculate the rotational partition function for a COmolecule at room temperature (300K), first using the exact formula 6.30 and then using the approximate formula 6.31

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