Equations 6.92 and 6.93 for the entropy and chemical potential involve the logarithm of the quantity VZintNvQ. Is this logarithm normally positive or negative? Plug in some numbers for an ordinary gas and discuss.

Short Answer

Expert verified

Yes, the logarithm is normally positive for ordinary gas as S=Nkln2is positive.

Step by step solution

01

Given information

We are given that,

Entropy and chemical potential involve the logarithm of the quantityVZintNvQ.

02

Explanation

We know that entropy is given as,

S=kNlnVN4πm3h2×UN32+52

Here, Uis the energy

and Vis volume

and Nis no. of molecules

Now, if energy and no. of molecules remain fixed,

S=NkVfVi

Here, Vfis the final volume

and Viis the initial volume

If Vf=2Vi

Then,

S=Nkln2

Similarly, the relationship between chemical potential can be determined to be positive.

From here, we can interpret that the logarithm of a given quantity is normally positive as both the entropy and chemical potential is positive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use Boltzmann factors to derive the exponential formula for the density of an isothermal atmosphere, already derived in Problems 1.16 and 3.37. (Hint: Let the system be a single air molecule, let s1 be a state with the molecule at sea level, and let s2 be a state with the molecule at height z.)

Use the Maxwell distribution to calculate the average value of v2for the molecules of an ideal gas. Check that your answer agrees with equation 6.41.

Show explicitly from the results of this section thatG=Nμfor an ideal gas.

Consider a large system of Nindistinguishable, noninteracting molecules (perhaps an ideal gas or a dilute solution). Find an expression for the Helmholtz free energy of this system, in terms of Z1, the partition function for a single molecule. (Use Stirling's approximation to eliminate the N!.) Then use your result to find the chemical potential, again in terms ofZ1.

This problem concerns a collection of N identical harmonic oscillators (perhaps an Einstein solid or the internal vibrations of gas molecules) at temperature T. As in Section 2.2, the allowed energies of each oscillator are 0, hf, 2hf, and so on. (

a) Prove by long division that

11-x=1+x+x2+x3+

For what values of x does this series have a finite sum?

(b) Evaluate the partition function for a single harmonic oscillator. Use the result of part (a) to simplify your answer as much as possible.

(c) Use formula 6.25 to find an expression for the average energy of a single oscillator at temperature T. Simplify your answer as much as possible.

(d) What is the total energy of the system of N oscillators at temperature T? Your result should agree with what you found in Problem 3.25.

(e) If you haven't already done so in Problem 3.25, compute the heat capacity of this system and check t hat it has the expected limits as T0 and T.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free