A cup containing 200g of water is sitting on your dining room table. After carefully measuring its temperature to be 20oC, you leave the room. Returning ten minutes later, you measure its temperature again and find that it is now 25oC. What can you conclude about the amount of heat added to the water? (Hint: This is a trick question.)

Short Answer

Expert verified

Amount of heat added is 4186 J.

Step by step solution

01

Given information

Mass of water, m=200 g = 0.2 kg
Difference in temperature, ΔT=(25-20)oC = 5oC
Specific of water, C=4186 J /kgK

02

Explanation

Amount of heat added can be calculated as

Q=m c ΔT

Substitute values and calculate

Q=mcT=(0.2kg)×(4186J/kg°C)×(5°C)Q=4186J

4186 Joule is added to the system.

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