At about what pressure would the mean free path of an air molecule at room temperature equal 10cm, the size of a typical laboratory apparatus?

Short Answer

Expert verified

The mean free path pressure is P=0.146Nm2

Step by step solution

01

Step: 1 To find pressure of mean free path:

The equation as

PV=NKT

V=π(2γ)2

By equating,

P=UT4πγ2λ

02

Subtituting the values 

subtituting the values of

T=100dr,γ=0.01,P=0.082N/m2as

P=1.381×1023×1004π×2×10102×0.01

P=0.274Nm2.

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