At the back of this book is a table of thermodynamic data for selected substances at room temperature. Browse through the CPvalues in this table, and check that you can account for most of them (approximately) using the equipartition theorem. Which values seem anomalous?

Short Answer

Expert verified

Short Answer:

For monoatomic gases: CP=20.775J·C-1

For diatomic gases: CP=29.085J·C-1

For polyatomic molecules: CP=33.24J·C-1

For a solid: CP=24.93J·C-1

Step by step solution

01

Given Information:

Table of thermodynamic data for selected substances at room temperature.

02

Step 1:

CP=8.311+32

For an ideal gas at constant pressure

CP=nR1+f2

In SI units, R=8.31.J·mol-1·K-1. So for one mole for an ideal gas:

Cp=8.311+f2

Because we have three transitional degrees of freedom in monatomic gases, f=3, the heat capacity of monatomic gases is:

CP=8.311+32

CP=20.775J·C-1

This is in great agreement with the monatomic gases hydrogen, argon, helium, and neon, according to the table in Schroeder's book's appendix.

03

Step 2:

We have three transitional degrees of freedom and two rotational degrees of freedom in diatomic gases (f=5). As a result, the heat capacity of diatomic gases is:

CP=8.311+62

CP=33.24J·C-1

which is quite close to the values for O2,N2and H2and CObut the heat capacity of Cl2is higher than this value.

04

Step 3:

With three transitional degrees of freedom, two rotational degrees of freedom, and one vibrational degree of freedom in a polyatomic molecule, f=0, the heat capacity of diatomic gases is:

CP=8.311+62

CP=33.24J·C-1

From the table, the heat capacity for carbon dioxide is CP=33.24J·C-1which is higher than CP=33.24J·C-1by 3.87

05

Step 4:

For most solids and liquids, the heat capacity at constant pressure is given by:

CP8.31f2

much then f=0 the heat capacity is therefore:

CP=8.3162

CP=24.93J·C-1

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Most popular questions from this chapter

When the temperature of liquid mercury increases by one degree Celsius (or one kelvin), its volume increases by one part in 550,000 . The fractional increase in volume per unit change in temperature (when the pressure is held fixed) is called the thermal expansion coefficient, β :
βΔV/VΔT
(where V is volume, T is temperature, and Δ signifies a change, which in this case should really be infinitesimal if β is to be well defined). So for mercury, β =1 / 550,000 K-1=1.81 x 10-4 K-1. (The exact value varies with temperature, but between 0oC and 200oC the variation is less than 1 %.)
(a) Get a mercury thermometer, estimate the size of the bulb at the bottom, and then estimate what the inside diameter of the tube has to be in order for the thermometer to work as required. Assume that the thermal expansion of the glass is negligible.
(b) The thermal expansion coefficient of water varies significantly with temperature: It is 7.5 x 10 -4 K-1 at 100oC, but decreases as the temperature is lowered until it becomes zero at 4oC. Below 4oC it is slightly negative, reaching a value of -0.68 x 10-4K-1 at 0oC. (This behavior is related to the fact that ice is less dense than water.) With this behavior in mind, imagine the process of a lake freezing over, and discuss in some detail how this process would be different if the thermal expansion coefficient of water were always positive.


Calculate the rms speed of a nitrogen molecule at room temperature.

The Rankine temperature scale(abbreviated °R) uses the same scale size degrees as Fahrenheit, but measured up from absolute zero like Kelvin(so Rankine is to Fahrenheit as Kelvin is to Celsius). Find the conversion formula between Rankine and Fahrenheit and also between Rankine and Kelvin. What is the room temperature on the Rankine scale?

For a solid, we also define the linear thermal expansion coefficient, α, as the fractional increase in length per degree:

αΔL/LΔT
(a) For steel, α is 1.1 x 10-5 K-1. Estimate the total variation in length of a 1 km steel bridge between a cold winter night and a hot summer day.
(b) The dial thermometer in Figure 1.2 uses a coiled metal strip made of two different metals laminated together. Explain how this works.
(c) Prove that the volume thermal expansion coefficient of a solid is equal to the sum of its linear expansion coefficients in the three directions β=αx + αy + αz. (So for an isotropic solid, which expands the same in all directions, β =3 α .)


When you're sick with a fever and you take your temperature with a thermometer, approximately what is the relaxation time?

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