Prove that if you had a refrigerator whose COP was better than the ideal value (4.9), you could hook it up to an ordinary Carnot engine to make an engine that produces no waste heat.

Short Answer

Expert verified

It is verified that a refrigerator with COP better than the ideal value can be hooked up to a Carnot engine to make an engine not producing waste heat.

Step by step solution

01

Concept Introduction

Let us write the expression of the ideal value of COP for Carnot engine

COP=TcoldTholTcoll

Here, Tcoldis temperature of the cold reservoir and Thotis temperature of hot reservoir.

02

Explanation

A refrigerator that has a coefficient of performance greater than the maximum Carnot value of COP requires an amount of work that is less than the work done in a Carnot engine.

A Carnot engine extracts heat from the hot reservoir and transfers it to the cold reservoir. The refrigerator, when hooked up to the Carnot engine, causes the composite system to yield a net surplus of work.

The compound system does not produce any waste heat because the refrigerator extracts the same amount of heat that the Carnot engine transfers.

03

Conclusion

Thus, it is verified that a refrigerator with COP better than the ideal value can be hooked up to a Carnot engine to make an engine not producing waste heat.

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Most popular questions from this chapter

A power plant produces1GWof electricity, at an efficiency of 40%(typical of today's coal-fired plants).

(a) At what rate does this plant expel waste heat into its environment?

(b) Assume first that the cold reservoir for this plant is a river whose flow rate is 100m3/s.By how much will the temperature of the river increase?

(c) To avoid this "thermal pollution" of the river, the plant could instead be cooled by evaporation of river water. (This is more expensive, but in some areas it is environmentally preferable.) At what rate must the water evaporate? What fraction of the river must be evaporated?

At a power plant that produces 1 GW109 watts) of electricity, the steam turbines take in steam at a temperature of 500o, and the waste heat is expelled into the environment at 20o
(a) What is the maximum possible efficiency of this plant?
(b) Suppose you develop a new material for making pipes and turbines, which allows the maximum steam temperature to be raised to 600o. Roughly how much money can you make in a year by installing your improved hardware, if you sell the additional electricity for 5 cents per kilowatt-hour? (Assume that the amount of fuel consumed at the plant is unchanged.)

A heat pump is an electrical device that heats a building by pumping heat in from the cold outside. In other words, it's the same as a refrigerator, but its purpose is to warm the hot reservoir rather than to cool the cold reservoir (even though it does both). Let us define the following standard symbols, all taken to be positive by convention:
Th=temperature inside buildingTc=temperature outsideQh=heat pumped into building in1dayQc=heat taken from outdoors in1dayW=electrical energy used by heat pump in1day
(a) Explain why the "coefficient of performance" (COP) for a heat pump should be defined as Qh / W.
(b) What relation among Qh , Qc, and W is implied by energy conservation alone? Will energy conservation permit the COP to be greater than 1 ?
(c) Use the second law of thermodynamics to derive an upper limit on the COP, in terms of the temperatures Th and Tc alone.
(d) Explain why a heat pump is better than an electric furnace, which simply converts electrical work directly into heat. (Include some numerical estimates.)

Prove directly (by calculating the heat taken in and the heat expelled) that a Carnot engine using an ideal gas as the working substance has an efficiency of1-tcth

Why must you put an air conditioner in the window of a building, rather than in the middle of a room?

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