In working high-pressure geochemistry problems it is usually more

convenient to express volumes in units of kJ/kbar. Work out the conversion factor

between this unit and m3

Short Answer

Expert verified

The conversion factor is1kJk·bar=10-5m3

Step by step solution

01

Step 1. Given information 

We used kJ/kbar as the unit of pressure in the high-pressure geochemical problem.

1kJkbar=1·103·J103·bar=1·Jbar

02

Calculation

Using the conversion between the units of pressure 1 bar = 105 Pa, we get

=1Jbar×lbar105N/m2=10-5JN/m2=10-5×N·MN/m2=10-5m31kJk·bar=10-5m3

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